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3 years ago

What does the word "atom" mean?

Chemistry

1 answer:

Artist 52 [7]3 years ago

7 0

cannot be cut into smaller pieces

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Energy and Temperature Activity Worksheet

NeTakaya

Answer:

the ground would heat up slower than the sand because it has lots of moisture so sand would heat up faster than any thing other than lava

Explanation:

7 0

3 years ago

Read 2 more answers

The final charge on each of the three separated spheres in part (b) is +3.0 μC. How many electrons would have to be added to one

marishachu [46]

Answer:

$1.873\times 10^{13}$ electrons should be added to one of these spheres to make it electrically neutral.

Explanation:

Total charge on each sphere = +3.0 μC = $3\times 10^{-6} C$

$1 \mu C=10^{-6} C$

In order to neutralize the positive charge equal magnitude of negative charge is to be added.

Total charge electrons, Q= -3.0 μC = $-3\times 10^{-6} C$

Number of electrons = n

Charge on a single electron, e = $-1.602\times 10^{-19} C$

Q = n × e

$-3\times 10^{-6} C=n\times (-1.602\times 10^{-19} C)$

$n=\frac{-3\times 10^{-6} C}{-1.602\times 10^{-19} C}=1.873\times 10^{13}$

$1.873\times 10^{13}$ electrons should be added to one of these spheres to make it electrically neutral.

4 0

3 years ago

How many liters of fat would have to be removed to result in a 5.2 lb weight loss? The density of human fat is 0.94 g/mL?

aksik [14]

I don’t even know I’m just answering for pints

7 0

3 years ago

Which is regarding enzyme inhbition

lys-0071 [83]

Explanation:

An enzyme inhibitor is a molecule that binds to an enzyme and decreases its activity. ... Since blocking an enzyme's activity can kill a pathogen or correct a metabolic imbalance, many drugs are enzyme inhibitors. They are also used in pesticides.

7 0

3 years ago

Calculate ∆G ◦ r for the decomposition of mercury(II) oxide 2 HgO(s) → 2 Hg(ℓ) + O2(g) ∆H◦ f −90.83 − − (kJ · mol−1 ) ∆S ◦ m 70.

bagirrra123 [75]

Answer:

4. +117,1 kJ/mol

Explanation:

ΔG of a reaction is:

ΔGr = ΔHr - TΔSr (1)

For the reaction:

2 HgO(s) → 2 Hg(l) + O₂(g)

ΔHr: 2ΔHf Hg(l) + ΔHf O₂(g) - 2ΔHf HgO(s)

As ΔHf of Hg(l) and ΔHf O₂(g) are 0:

ΔHr: - 2ΔHf HgO(s) = 181,66 kJ/mol

In the same way ΔSr is:

ΔSr= 2ΔS° Hg(l) + ΔS° O₂(g) - 2ΔS° HgO(s)

ΔSr= 2* 76,02J/Kmol + 205,14 J/Kmol - 2*70,19 J/Kmol

ΔSr= 216,8 J/Kmol = 0,216 kJ/Kmol

Thus, ΔGr at 298K is:

ΔGr = 181,66 kJ/mol - 298K*0,216kJ/Kmol

ΔGr = +117,3 kJ/mol ≈ 4. +117,1 kJ/mol

I hope it helps!

5 0

3 years ago