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likoan [24]
3 years ago
12

I have a lot of algebra problems who can help i will fan medal

Mathematics
1 answer:
dangina [55]3 years ago
4 0
I think I can! I recently covered algebra in 6th grade, (if that's what grade ur in) and I'm pretty good at 6th grade algebra
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Can a ray have two in point
Burka [1]
No i ray cannot have two end points. A ray only has one line that keeps on going and the other side has a endpoint where it does not keep on going like a line.
Hope this helps. (:
5 0
3 years ago
Read 2 more answers
Can someone help me ???
ira [324]
The square root of 72 is rational because the answer can be a real number.
4 0
3 years ago
One mile is equal to 5,280 feet. What is the sum of the lengths of all 18 holes on the golf course in miles?
soldi70 [24.7K]

Answer:

the answer would be 4 Miles.

explanation:

We already know that 5,280 feet equals 1 Mile, and so we divide-

21,120 divided by 5,280, and that equals 4.

hope that made sense! I’m not very good with wording things! :)

8 0
3 years ago
Of the 12 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees a
Ivenika [448]

Answer:

<h2>70 possible groups</h2>

Step-by-step explanation:

Given the total number of employee to be equal to 12 temporary employee.

Number of women employee = 5 women

Number of men employee = 12 - 5 = 7 men

If 4 will be hired as permanent employees, the possible ways they can be grouped so that the 4 temporary employees consists of 3 women and 1 man can be done by applying the combination formula.

Combination has to do with selection. For example, if r objects are to be selected from n pool of similar objects, this can be done in <em>nCr </em>different ways.

nCr = \frac{n!}{(n-r)!r!}

According to question, we are to select 3 women from 5 women and 1 man from 7 men. Based on similarity in sex, this can be done in (5C3* 7C1) different ways .

5C3 * 7C1\\=  \frac{5!}{(5-3)!3!} * \frac{7!}{(7-1)!1!}\\\\= \frac{5!}{2!3!} * \frac{7!}{6!1!}\\\\=  \frac{5*4*3!}{3!*2} * \frac{7*6!}{6!*1}\\\\= \frac{20}{2} * \frac{7}{1}\\  \\= 10*7\\\\= 70\ possible\ groups

8 0
3 years ago
(mx+8)(2x-4) what is the value of m?
Kobotan [32]
You can't find m , is that the original equation?
7 0
3 years ago
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