A)CH3OCH3 is the isomer of CH3CH2OH
One kilogram is equal to one thousand grams. Further, one gram is equal to 1000 mg. The conversion is as shown below,
(6.285 x 10³ mg) x (1 g / 1000 mg) x (1 kg / 1000 g)
The numerical value of the operation above is 0.006285 kg.
Answer:
Less than 22 grams because some mass is lost in the reaction
Explanation:
Took the test on K12
Ba(OH)2 is an basic solution. It has more OH- ions than H+ ions. pOH should be calculated to find out its pH
The reaction is
Ba(OH)2 ⇒ Ba2+ (aq) + 2 OH-(aq)
One mole barium hydroxide releases 2 moles hydroxide ions.
Use that ratio to calculate molarity (M) of OH- ions [OH-]. The ratio is 1:2.
0.10 M Ba(OH)2 release 2*0.10 M= 0.02 M OH- ions
[OH-]= 0.02
pOH= - log [OH-] = - log 0.02 = 1.7
Thats not the answer! We found pOH of the solution before titration.
pH and pOH relationship is shown by formula of pH+pOH= 14
pH= 14-pOH
pH= 14-1.7= 12.3
Answer:
Molecular formula of cyanogen is C₂N₂
Explanation:
We apply the ideal gases law to find out the mole of cyanogen
P . V = n. R. T
Firstly let's convert the pressure in atm, for R
750 mmHg = 0.986 atm
25°C + 273 = 298K
0.986 atm . 0.714L = n . 0.082 L.atm/mol.K .298K
(0.986 atm . 0.714L) / (0.082 L.atm/mol.K .298K) = n
0.0288 mol = n
Molar mass of cyanogen = mass / mol
1.50 g /0.0288 mol = 52.02 g/m
Let's apply the percent, to know the quantity of atoms
100 g of compound contain 46.2 g of C and 53.8 g of N
52.02 g of compound contain:
(52.02 . 46.2) / 100 = 24 g → 2 atoms of C
(52.02 . 53.8) / 100 = .28 g → 2 atoms of N
