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daser333 [38]
2 years ago
15

Why do elements form an ionic bond

Chemistry
1 answer:
Lelu [443]2 years ago
5 0

Answer:

An ionic bond is formed when a metallic element and a non-metallic element form a compound.

Explanation:

As you may know, each atom contains a set amount of electrons. For example, Hydrogen has one electron, helium has two electrons, lithium has three electrons and so on.

Electrons come in shells. The first shell can hold 2 elections at most, and each shell past this point can hold 8 electrons. When an atom has a filled outer shell, it is considered stable. (This so why the noble gases are unreactive- they have a full outer shell of electrons.)

This is why compounds can form- it is the chemical bonding of 2 or more chemical elements: take NaCl, sodium chloride, or SO2, sulphur dioxide.

You specifically asked about ionic bonds. Ionic bonds, as expressed above, form between a compound of a metallic and non metallic element.

Let's take sodium chloride as an example. Sodium has 1 electron in its outer shell and chlorine has 7. Both need a full outer shell to become stable. Because of this, the sodium atom loses its only electron in its outer shell to become a sodium ion and the chlorine atom gains the electron to become a chlorine ion as well. Because of this, both ions have a full outer shell, rendering them stable.

Now, because the sodium ion is short of one electron, it has more protons than electrons, resulting in it having a positive charge. The chlorine ion is the opposite, having a negative charge.

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When molten sulfur reacts with chlorine gas, a vile-smelling orange liquid forms that has an empirical formula of SCl. The struc
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Answer:

The structure is shown below.

Explanation:

The formal charge (FC) is the charge that is more close to the actual charge in the real molecules and ions. It can be calculated based on the number of valence electrons (V), the shared electrons (S) and the electrons in the lone pairs (L) by the equation:

FC = V - (L + S/2)

Sulfur is in group 16 of the periodic table, so it has 6 valence electrons, and chlorine is from group 17 of the periodic table, and so it has 7 valence electrons. Chlorine can share only one electron, so it is stable. Sulfur can expand its octet (because it's from the third period) and can have more than 8 electrons when stable.

The possible formulas, from the empiric one, are:

SCl, S₂Cl₂, and S₃Cl₃.

To have FC = 0, chlorine must done only one bond, because S = 2, and L = 6, so:

FC = 7 - (6 + 2/2) = 0

So, it can not be the central atom of a structure. In the SCl, it will hav only a simple bond, so for sulfur, S = 2, and L = 4 (only the lone pairs are counted)

FC = 6 - (4+ 2/2) = +1

For S₂Cl₂, the two sulfurs must be bonded to a simple bond, and each one to one chlorine, thus, for both od them S = 4, and L = 4. so

FC = 6 - (4 + 4/2) = 0

So, it is the correct structure. The lewis structure represents the bonds by lines and the lone pairs of electrons by dots, and it is shown below.

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