What are all the real zeroes of y = (x –12)^3 – 7
2 answers:
You might be right.
Let y = 0
(x - 12)^3 - 7 = 0 Subtract 7 from both sides
(x - 12)^3 = 7 Take the cube root of both sides.
x - 12 = cuberoot(7) Add 12 to both sides
x = 12 + cuberoot(7)
Are the other two real or imaginary? The quickest way to find out the answer is to graph the original equation. It has the shape of something that crosses the x axis but once. So the other two roots are imaginary.
My calculator says that the real root is 13.91
The two complex ones are 11.04 +/- 1.66i which of course is not real.
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Answer:
<em>The dimensions of the tabletop: Length= 67.976... inches and Width= 33.988... inches and the perimeter will be 203.929... inches.</em>
Step-by-step explanation:
Suppose, the width of the rectangular tabletop is inch.
As the tabletop has a length that is twice it’s width, so the length will be: inch.
The tabletop measures 76 inches on its diagonal.
<u>Formula for length of diagonal of rectangle</u>:
So, the equation will be..........
Thus, the width of the tabletop is 33.988... inches and the length will be: (2×33.988...) = 67.976... inches.
The perimeter will be: 2(33.988...+ 67.976...) inches = 203.929... inches.