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3 years ago

What are all the real zeroes of y = (x –12)^3 – 7

Mathematics

2 answers:

kodGreya [7K]3 years ago

8 0

y = (x –12)^3 – 7

set y=0

0 = (x –12)^3 – 7

add 7 to each side

7 = (x –12)^3

take the cube root of each side

7^ 1/3 = x-12

add 12 to each side

12 + 7^(1/3) = x

this is the only real root

the other 2 are imaginary

Delvig [45]3 years ago

3 0

You might be right.

Let y = 0

(x - 12)^3 - 7 = 0 Subtract 7 from both sides

(x - 12)^3 = 7 Take the cube root of both sides.

x - 12 = cuberoot(7) Add 12 to both sides

x = 12 + cuberoot(7)

Are the other two real or imaginary? The quickest way to find out the answer is to graph the original equation. It has the shape of something that crosses the x axis but once. So the other two roots are imaginary.

My calculator says that the real root is 13.91

The two complex ones are 11.04 +/- 1.66i which of course is not real.

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5. Melanie can run around the track 9 times

Zina [86]

Answer: 3.36

Step-by-step explanation: 75minutes / 28= 2.678571428571429

9/2.678571428571429=3.36 times

3 0

3 years ago

Read 2 more answers

A girl ran from her home to a store at the rate of 6 mph, and she walked back home at the rate of 4 mph. if it took 15 minutes f

viva [34]

Home is 0.6 miles away from the store

How to solve such time related questions?

The key concept for solving such questions is the relationship between speed, distance and time.

The relationship between them is Distance = Speed x Time

Given:-

Total time taken by girl to complete the trip = 15 minutes = $\frac{1}{4}$ hours

Speed while riding going = 6 miles per hour

Speed while coming back = 4 miles per hour

Total time taken by girl =

Time taken while going + Time taken while coming back - (1)

Let x be distance from home to store

$\frac{x}{6}$ = Time taken while going

$\frac{x}{4}$ = Time taken while coming back

Substituting in (1) we get

$\frac{1}{4} = \frac{x}{6} + \frac{x}{4}$

$\frac{1}{4} = \frac{2x + 3x}{12}$

$\frac{1}{4} = \frac{5x}{12}$

$x= \frac{12}{20}$

x = 0.6 miles

Thus home is 0.6 miles away from the store

Learn more about time related here :

brainly.com/question/12759408

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6 0

1 year ago

Two mechanics worked on a car. the first mechanic worked for 10 hours, and the second mechanic worked for 15 hours. together the

Yuliya22 [10]

Let x and y be the rate per hour for Mechanic 1 and 2 respectively.

Then,
x+y=205 ---------- (1)
Additionally,
10x+15y = 2500 ------ (2)

Solving equations 1 and 2;
Multiply (1) by 10 and subtract two from the result,
10x+10y = 2050
10x +15 y =2500
----------------------
-5 y = --450 => y = 450/5 = $90
Then,
x= 205-90 = $115

Therefore,
Mechanic 1 charged $115 per hour
Mechanic 2 charged $90 per hour

3 0

3 years ago

Let f(x) = 8x3 − 22x2 − 4 and g(x) = 4x − 3. Find f of x over g of x

SVEN [57.7K]

F(x) = 8x³ - 22x² - 4
g(x) = 4x - 3

$(f \div g)(x) = \frac{8x^{3} - 22x^{2} - 4}{4x - 3}$
$(f \div g)(x) = \frac{2(4x^{3}) - 2(11x^{2}) - 2(2)}{4x - 3}$
$(f \div g)(x) = \frac{2(4x^{3} - 11x^{2} - 2)}{4x - 3}$

3 0

2 years ago

Read 2 more answers

Awnser please please

astraxan [27]

They're all d).

1) 28>24=10+14

2) Either 96/8=? or 8*?=96 describe the problem, ? being the number of chairs (the blank square in the answers). Of the two only the first appears in the options.

3) This question is ambiguous: if someone went both days, we could say the total number of people who went to the Saturday and Sunday games would be less than 3271+5844=9115. But who wrote the question likely wanted you to just do the sum between the two numbers, so of all options d is likely what they want you to choose.

6 0

2 years ago