Question

If f(x)= 2^x, then f(log to the base 2 (5))=

Answer 1

Let's plug the value:

$f(x)=2^x \implies f(\log_2(5))=2^{\log_2(5)}$

Recall that exponent and logarithm are inverse operations:

$a^{\log_a(b)}=b$

So, we have

$2^{\log_2(5)}=5$