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LuckyWell [14K]
3 years ago
9

Trent's salary used to be $143,020. After changing the amount of time he works, he has begun earning $78,661. By what percent di

d Trent's salary decrease?
Mathematics
1 answer:
svlad2 [7]3 years ago
6 0

Answer:

The salary decreased by 45%

Step-by-step explanation:

Given,

The previous salary of Trent is $143,020

The current salary of Trent is $78,661

The decrease in salary is ($143,020 - $78,661) = $64,359

When he used to get $143,020, the decrease in salary is = $64,359

When he used to get $1, the decrease in salary is = $64,359/$143,020

When he used to get $100, the decrease in salary is = $(64,359/143,020)*100

                                                                                        = 45%

Therefore, there is a decrease in salary by 45%.

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One point on the trend line is 200,6 using this point and the y-intercept find the slope of the trend line.
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Step-by-step explanation:

Use the formula (Y2 - Y1)/(X2 - X1) to find the slope between two points

We'll make Point 1 (which is X1 and Y1) the Y-intercept so

X1, Y1 = (0, 5.00)

And we'll make Point 2 (which is X2 and Y2) the point on the trend line

X2, Y2 = (200, 6.00)

Plug into the formula:

(6.00 - 5.00)/(200 - 0)

= 1/200 or 0.005

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6 0
3 years ago
Hey can you help me answer this question by giving me the answer?
Leto [7]

The value of f(a)=4-2a+6a^{2}, f(a+h) is 6a^{2} +6h^{2} -2a-2h+12ah , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6x^{2}.

Given a function f(x)=4-2x+6x^{2}.

We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.

Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.

f(a)=4-2a+6a^{2} (By just putting x=a).

f(a+h)==4-2(a+h)+6(a+h)^{2}

=4-2a-2h+6(a^{2} +h^{2} +2ah)

=4-2a-2h+6a^{2} +6h^{2} +12ah

=6a^{2} +6h^{2}-2a-2h+12ah

[f(a+h)-f(a)]/h=[6a^{2} +6h^{2}-2a-2h+12ah-(4-2a+6a^{2} )]/h

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=6h+12a-2.

Hence the value of function f(a)=4-2a+6a^{2}, f(a+h) is 6a^{2} +6h^{2} -2a-2h+12ah , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6x^{2}.

Learn more about function at brainly.com/question/10439235

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Step-by-step explanation:

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