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ICE Princess25 [194]
3 years ago
9

Amanda needs to create an informative print brochure for her local library’s fundraiser dinner. What critical detail must she ha

ve before she starts designing the brochure?
A. target audience for the brochure
B. font styles for the brochure
C. delivery format of the brochure
D. artwork for the brochure
Computers and Technology
1 answer:
Charra [1.4K]3 years ago
5 0

Answer: A. target audience for the brochure.

Before even starting the design of the brochure, Amanda needs to get information on who the target audience are going to be. Amanda will need to conduct a quick research on what the audience of their community likes and does not like. By understanding the target audience, Amanda will be able to get an idea of what design, colors, and format she would make that will attract the attention of their audience.

You might be interested in
Write an HLA Assembly language program that prompts for a specific int8 value named n and then displays a repeated digit pattern
yan [13]

Answer:

Output:

123456

123456

123456

123456

123456

123456

Explanation:

C Code:

#include <stdio.h>

int main() {

int n,i,j;

printf("Gimme a decimal value to use as n:");

scanf("%d",&n);

for(i=0;i<n;i++){

for(j=1;j<=n;j++){

printf("%d",j);

}

printf("\n");

}

return 0;

}

Equivalent assembly program:

.LC0:

.string "Gimme a decimal value to use as n:"

.LC1:

.string "%d"

main:

push rbp

mov rbp, rsp

sub rsp, 16

mov edi, OFFSET FLAT:.LC0

mov eax, 0

call printf

lea rax, [rbp-12]

mov rsi, rax

mov edi, OFFSET FLAT:.LC1

mov eax, 0

call scanf

mov DWORD PTR [rbp-4], 0

.L5:

mov eax, DWORD PTR [rbp-12]

cmp DWORD PTR [rbp-4], eax

jge .L2

mov DWORD PTR [rbp-8], 1

.L4:

mov eax, DWORD PTR [rbp-12]

cmp DWORD PTR [rbp-8], eax

jg .L3

mov eax, DWORD PTR [rbp-8]

mov esi, eax

mov edi, OFFSET FLAT:.LC1

mov eax, 0

call printf

add DWORD PTR [rbp-8], 1

jmp .L4

.L3:

mov edi, 10

call putchar

add DWORD PTR [rbp-4], 1

jmp .L5

.L2:

mov eax, 0

leave

ret

Input:

6

The program was first written with a c code, anf and subsequently translated to an assembly language.

3 0
3 years ago
What is the channel capacity for a teleprinter channel with a 300 Hz bandwidth and a signal-to-noise ratio of 30dB, where the no
wolverine [178]

Answer:

The answer is 2988 bits per seconds

Explanation:

Solution

Given that:

Bandwidth (B) = 300Hz

Signal to noise ratio (SNR) = 30dB

Now let C = channel capacity

Using  Deubel formula we have the following:

SNR db = 10* log (SNR)

30 =10* log (SNR)

So,

SNR =log^⁻1 (3)

SNR = (10)^3

SNR = 1000

Thus SNR =1000

Now

Applying the Shannon's equation

C = B * log₂ ( 1 + SNR)

C = 300 * log₂ ( 1 + 1000)

C = 300 * log₂ (1001)

C = 300 * 9.96

C =2988

Hence the capacity of the channel for teleprinter channel is 2988 bits per second.

8 0
4 years ago
What can a human till do better and fater than any Machine Learning (ML) olution?
Gemiola [76]

Judge the quality of any given data can a human till do better and fater than any Machine Learning (ML).

<h3>What is Machine Learning (ML)?</h3>
  • Switch between fields of expertise. a thorough understanding of the facts' meaning. Check the veracity of any information that is provided.
  • According to some scientists, AI will replace jobs with a single output. A mental task may also be mechanized in the future if it can be finished by a person in less than a second.
  • Expressing empathy, making others feel good, taking care of others, expressing feelings and vulnerability in a sympathetic way, and making people laugh are all examples of being creative and artistic for the purpose of being creative. The personal touch is important in most occupations and, in certain cases, it completes the task entirely.
  • Machines can perform as well as or better than humans in some tasks, despite their slower rate of development.

To learn more about Machine Learning (ML) refert to:

brainly.com/question/25523571

#SPJ4

5 0
1 year ago
HELP ASAP
saw5 [17]

When associating an event handler with a button click which event occurs  the user hits the right mouse button, the outcome, if any, is That hurt.

How can the result be established?

The flow of the programme indicates that:

When the user presses the button, the application prints "That hurt" without any quotation marks.

This operation may be found in the third line of the programme.

Therefore, the outcome is (b) That hurt if the user clicks the right mouse button.

Details on the programme are available at:

brainly.com/question/16397886

#SPJ4

7 0
1 year ago
Read 2 more answers
Dr. Watson has been kidnaped! Sherlock Holmes was contacted by the kidnapper for ransom. Moments later he received a message fro
adelina 88 [10]

Answer:

please mark me brainlist

Explanation:

This algorithm works for n number of strings in python3

Input:

83217

8213897

683147

Output:

837

from itertools import product

import pdb

import numpy as np

def neigh(index):

N = len(index)

for ri in product((0, -1), repeat=N):

if not all(i == 0 for i in ri):

yield tuple(i + i_rel for i, i_rel in zip(index, ri))

def longestCommonSubSequenceOfN(sqs):

numberOfSequences = len(sqs); # to know number of sequences

lengths = np.array([len(sequence) for sequence in sqs]); # to know length of each sequences placed in # array

incrLengths = lengths + 1; # here we are taking no .of sequences +1

lengths = tuple(lengths); # making lengths into tuple to make it mutable

inverseDistances = np.zeros(incrLengths);

ranges = [tuple(range(1, length+1)) for length in lengths[::-1]]; # finding ranges from 1 to each lengths

for tupleIndex in product(*ranges):

tupleIndex = tupleIndex[::-1];

neighborIndexes = list(neigh(tupleIndex)); # finding neighbours for each tupled index value and # store them in list

operationsWithMisMatch = np.array([]); # creating array which are miss matched

 

for neighborIndex in neighborIndexes:

operationsWithMisMatch = np.append(operationsWithMisMatch, inverseDistances[neighborIndex]);

#appending newly created array with operations miss match and inverseDistances

operationsWithMatch = np.copy(operationsWithMisMatch);

# copying newly generated missmatch indexs

operationsWithMatch[-1] = operationsWithMatch[-1] + 1;

# incrementing last indexed value

chars = [sqs[i][neighborIndexes[-1][i]] for i in range(numberOfSequences)];

# finding a string(chars) with neighbour indexes and checking with other sequences

if(all(elem == chars[0] for elem in chars)):

inverseDistances[tupleIndex] = max(operationsWithMatch);

else:

inverseDistances[tupleIndex] = max(operationsWithMisMatch);

 

subString = ""; # resulted string

mainTupleIndex = lengths; # copying lengths list to mainTupleIndex

while(all(ind > 0 for ind in mainTupleIndex)):

neighborsIndexes = list(neigh(mainTupleIndex));

#generating neighbour indexes with main tuple index in form of list

anyOperation = False;

for tupleIndex in neighborsIndexes:

current = inverseDistances[mainTupleIndex];

if(current == inverseDistances[tupleIndex]): # comparing indexes in main tuple index and inverse #distance tuple index

mainTupleIndex = tupleIndex;

anyOperation = True;

break;

if(not anyOperation): # if anyoperation is False then we are generating sunString

subString += str(sqs[0][mainTupleIndex[0] - 1]);

mainTupleIndex = neighborsIndexes[-1];

return subString[::-1]; # reversing resulted string

sequences = ["83217", "8213897", "683147"]

print(longestCommonSubSequenceOfN(sequences)); #837

8 0
3 years ago
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