Answer:
Hiiiii
I'm okay, how about you?
thanks for the free points! :)
Percent of free throws = (number of free throws made / total attempts) x 100
Percent = (80/100) x 100 = 80%
The answer is 80%
Answer:
18x^2
Step-by-step explanation:
You're basically just multiplying them together :)
Answer:
p value = 0.03514
Step-by-step explanation:
Hypotheses would be

(left tailed test at 10% level of significance)
Here p stands for the sample proportion of mothers smoked more than 21 cigarettes during their pregnancy.
Sample size =130
persons who smoked = 2
Sample proportion = 
Assuming H0 to be true
Std error= 
p difference = -0.0346
Test statistic z=-1.81
p value = 0.03514
Since p is less than 0.10, significance level, we reject H0