Can y’all help me with this question?

MrRa [10]

$6.2 = 1.2\pi\sqrt{L(0.0001)}$
$\frac{6.2}{1.2\pi} = \frac{1.2\pi\sqrt{L(0.0001)}}{1.2\pi}$
$1.644601079 = \sqrt{L(0.0001)}$
$(1.644601079)^{2} = (\sqrt{L(0.0001)})^{2}$
$2.704712708 = L(0.0001)$
$\frac{2.704712708}{0.0001} = \frac{L(0.0001)}{0.0001}$
$27047127.08 = L$

I had to divide each number by 1.2π, make sure that it can be multiplied by itself twice, and have to divide it by 0.0001 to find out what L is equal to.

7 0

4 years ago

The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). What is the stan

Crank

Answer:

Step-by-step explanation:

We are given coordinates of the line passed through (–5, –1) and (10, –7) .

Applying slope formula,

$Slope=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-5,\:-1\right),\:\left(x_2,\:y_2\right)=\left(10,\:-7\right)$

Therefore,

$m=\frac{-7-\left(-1\right)}{10-\left(-5\right)}$

$m=-\frac{2}{5}$

Therefore, slope is $m=-\frac{2}{5}$ .

Applying point-slope form $y-y_1=m(x-x_1),$ we get

$y+7 = -\frac{2}{5}(x-10)$

$y+7=-\frac{2}{5}(x-10)$

On multiplying both sides by 5, we get

$5(y+7)=5\times-\frac{2}{5}(x+1)$

5y+35=-2(x-10)

5y+35=-2x+20

Adding 2x on both sides, we get

5y+25+2x=-2x+20+2x

2x+5y+35=20

Subtracting 35 from both sides, we get

2x+5y+35-35=20-35

2x+5y=-15.

Therefore, required equation is :

6 0

3 years ago

Allied Corporation is trying to sell its new machines to Ajax. Allied claims that the machine will pay for itself since the time

kvasek [131]

Answer:

z(s) is in the acceptance region. We accept H₀ we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

Step-by-step explanation:

We must evaluate the differences of the means of the two machines, to do so, we will assume a CI of 95%, and as the interest is to find out if the new machine has better performance ( machine has a bigger efficiency or the new machine produces more units per unit of time than the old one) the test will be a one tail-test (to the left).

New machine

Sample mean x₁ = 25

Sample variance s₁ = 27

Sample size n₁ = 45

Old machine

Sample mean x₂ = 23

Sample variance s₂ = 7,56

Sample size n₂ = 36

Test Hypothesis:

Null hypothesis H₀ x₂ - x₁ = d = 0

Alternative hypothesis Hₐ x₂ - x₁ < 0

CI = 90 % ⇒ α = 10 % α = 0,1 z(c) = - 1,28

To calculate z(s)

z(s) = ( x₂ - x₁ ) / √s₁² / n₁ + s₂² / n₂

s₁ = 27 ⇒ s₁² = 729

n₁ = 45 ⇒ s₁² / n₁ = 16,2

s₂ = 7,56 ⇒ s₂² = 57,15

n₂ = 36 ⇒ s₂² / n₂ = 1,5876

√s₁² / n₁ + s₂² / n₂ = √ 16,2 + 1.5876 = 4,2175

z(s) = (23 - 25 )/4,2175

z(s) = - 0,4742

Comparing z(s) and z(c)

|z(s)| < | z(c)|

z(s) is in the acceptance region. We accept H₀ we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

The very hight dispersion of values s₁ = 27 is evidence of frecuent values quite far from the mean

3 0

3 years ago

How many solutions does this linear system have?

gayaneshka [121]

Answer:

One solution: (2.5,0)

Step-by-step explanation:

We can use substitution for the solution. Substitute y=2x-5 to -8x-4y=-20 so that you end up with -8x-8x+20=-20. Next you want to add like terms which will be -16x+20=-20, next you want isolate x by subtracting 20 from both sides and leaves you with -16x=-40. Divide -16 on both sides to fully isolate x and will leave you with x=2.5. Now substiture in 2.5 for x in y=2x-5 to get y=2(2.5)-5 which will then lead to y=0.

4 0

3 years ago

HOW do you find the value of TAN 88 degrees 22' 45'' and COT 36 degrees???

storchak [24]

Part 1
We want to find the tan of 88 degrees, 22' 45''.

88° 22' 45''
= 88 + 22/60 + 45/3600 degrees
= 88.3792°

From the calculator, obtain
tan(88.3792°) = 35.3409

Answer: 35.3409

Part 2
We want to find cot(36°).

By definition, cot(x) = 1/tan(x).
From the calculator, obtain
tan(36°) = 0.7265
Therefore
cot(36°) = 1/0.7265 = 1.3764

Answer: 1.3764

3 0

4 years ago