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Alenkinab [10]
3 years ago
7

Select the things that would happen if the Moon were to vanish. (You may select more than one.)

Physics
1 answer:
Trava [24]3 years ago
3 0

Answer:

The Answer Is A,C,D

Explanation:

The gravitational pull from the moon make bigger waves'

There would be no moon for eclipses

There would be more sun and no moon

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A stunt driver rounds a banked, circular curve. The driver rounds the curve at a high, constant speed, such that the car is just
bagirrra123 [75]

Answer: C

Frictional force

Explanation:

The description of the question above is an example of a circular motion.

For a car travelling in a curved path, the frictional force between the tyres and the road surface will provide the centripetal force.

Since the road is banked, and the cross section of the banked road is constructed like a ramp. The car drives transversely to the slope of the ramp, so that the wheels of one side of the car are lower than the wheels on the other side of the car, for cornering the banked road, the car will not rely only on the frictional force.

Therefore, the correct answer is option C - the frictional force.

5 0
4 years ago
What drives plate tectonics in the earths interior
xxTIMURxx [149]
The convection going on with the magma in the asthenosphere
4 0
3 years ago
Read 2 more answers
An energy storage system based on a flywheel (a rotating disk) can store a maximum of 3.7 MJ when the flywheel is rotating at 16
Likurg_2 [28]

The moment of inertia of the flywheel is 2.63 kg-m^{2}

It is given that,

The maximum energy stored on the flywheel is given as

E=3.7MJ= 3.7×10^{6} J

Angular velocity of the flywheel is 16000\frac{rev}{min} = 1675.51\frac{rad}{sec}

So to find the moment of inertia of the flywheel. The energy of a flywheel in rotational kinematics is given by :

E = \frac{1}{2}Iw^{2}

By rearranging the equation:

I = \frac{2E}{w_{2} }

I = 2.63 kg-m^{2}

Thus the moment of inertia of the flywheel is 2.63 kg-m^{2}.

Learn more about moment of inertia here;

brainly.com/question/13449336

#SPJ4

7 0
2 years ago
A man is walking away from a lamppost with a light source h = 6 m above the ground. the man is m = 2 m tall. how long is the man
Llana [10]

Answer;

= 4 m is the length of the man's shadow.

Explanation;

2/x=6/(8+x) cross multiply.

6x=2(8+x)

6x=16+2x

6x-2x=16

4x=16

x=2=16/4

x=4 m. is the length of the man's shadow.

3 0
3 years ago
A box with a mass of 12.5kg sits on the floor how high would you need to lift it has a GPE of 568j
Degger [83]
GPE=mgh
m= 12.5kg
g= 9.81 always
h=?

568=12.5*9.81*h
Solve for h
You will get 4.63m
4 0
3 years ago
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