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anastassius [24]
3 years ago
10

carrier. In a later maneuver, the jet comes in for a landing on solid ground with a speed of 100 m/s, and its acceleration can h

ave a maximum magnitude of 5.00 m/s2 as it comes to rest. (a) From the instant the jet touches the runway, what is the minimum time interval needed before it can come to rest
Physics
1 answer:
GREYUIT [131]3 years ago
6 0

Answer:

The time required for the plane to slow down from the moment it touches the ground is 20 seconds.

Explanation:

t = Time taken for jet to stop

u = Initial velocity = 100 m/s

v = Final velocity = 0

s = Displacement

a = Acceleration = -5.00 m/s² (slowing down)

Equation of motion

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-100}{-5}\\\Rightarrow t=20\ s

The time required for the plane to slow down from the moment it touches the ground is 20 seconds.

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A railroad car of mass M moving at a speed v1 collides and couples with two coupled railroad cars, each of the same mass M and m
Tatiana [17]

Answer:

Explanation:

Given

mass of each railroad is M

first railroad is moving with velocity v_1 and other two's with v_2

conserving Momentum

Mv_1+2Mv_2=3M v_f

where v_f is the final velocity of combined system

v_f=\frac{v_1+2v_2}{3}

(b)Initial Kinetic Energy

=\frac{1}{2}Mv_1^2+\frac{1}{2}2Mv_2^2

=\frac{1}{2}Mv_1^2+Mv_2^2

Final Kinetic Energy

=\frac{1}{2}3Mv_f^2=\frac{1}{6}M(v_1^2+4v_2^{2}+4v_{1}v_2)

Loss in Kinetic Energy

=\frac{1}{2}Mv_1^2+Mv_2^2-\frac{1}{6}M(v_1^2+4v_2^{2}+4v_{1}v_2)

=M(v_1-v_2^2)^2

7 0
4 years ago
If you want to calculate the acceleration of a car, you should _____ the change in velocity of the car by the time interval.
Neporo4naja [7]

Answer:

Your awnser is B. Increase

Explanation:

5 0
3 years ago
Read 2 more answers
How is sound produced by using pipel wind instruments​
AlekseyPX
The air inside the pipes of a wind instrument vibrates. ... The result is longitudinal standing waves in the air column inside the pipe. The ends, whether open or closed, create nodes or antinodes in these standing waves.
5 0
3 years ago
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Hot air balloon with a kinetic energy of 76550J and a mass of 1890kg.<br> what’s the velocity?
lukranit [14]

Answer:

K.E =  \frac{1}{2} m {v}^{2}  \\ 76550 = \frac{1}{2} (1890) {v}^{2} \\  {v}^{2}  =  \frac{76550}{945}  \\  = 81.005 \\ v =  \sqrt{81.005}  \\ v  \approx \: 9m. {sec}^{ - 1}

6 0
3 years ago
A vertical spring with k=490N/m is standing on the ground. You are holding a 5.0kg block just above the spring, not quite touchi
WARRIOR [948]

Answer:

Compression in the spring, x = 0.20 m

Explanation:

Given that,

Spring constant of the spring, k = 490 N/m

Mass of the block, m = 5 kg

To find,

Compression in the spring.

Solution,

Since the block is suddenly dropped on the spring gravitational potential energy of block converts into elastic potential energy of spring. Its expression is given by :

mgx=\dfrac{1}{2}kx^2

Where

x is the compression in the spring

x=\dfrac{2mg}{k}

x=\dfrac{2\times 5\times 9.8}{490}

x = 0.20 m

So, the compression in the spring due to block is 0.20 meters.

5 0
3 years ago
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