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Zinaida [17]
2 years ago
12

A paragraph that can serve the specific purpose of creating a special effect within the essay is called?

Physics
2 answers:
Katarina [22]2 years ago
7 0
Its b.functional paragraph because writers use this for interest presents and special effects
fomenos2 years ago
3 0

Answer:

b. functional paragraph

Explanation:

A paragraph is a communicative unit formed by a set of sequential sentences that deals with the same topic. It is composed of a set of sentences that have a certain thematic unit or that, without having it, are enunciated together. It is a component of the text that in its external aspect begins with a capital letter and ends in a separate point. It includes several related sentences on the same sub-theme; One of them expresses the main idea.

<u>Functional paragraph</u>

Within the formal structure of the text, they play a role not so much in content development, but rather in keeping the informational fabric organized and related to each other. They are usually short paragraphs that help guide the exposition of thought, relating some paragraphs to others to contribute to unity, cohesion and coherence of the text. These paragraphs do not have a thematic sentence that expresses a central idea, since their prayers only collaborate with the development of the main propositions contained in the informative paragraphs that precede or follow them. They can be of three kinds:

Heading or introductory paragraphs: As the name implies, its function is to introduce or present the topic. You must also locate the reader and arouse his interest.

Link or transition paragraphs: They relate the information in one paragraph with that in another. Some are retrospective (when referring to information already presented) and others, prospective (when they announce information that will appear later). They can be considered as major connectors that contribute to the unity, cohesion and coherence of the text.

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In a laboratory, you determine that the density of a certain solid is 5.23× 10 −6 kg/m m 3 . convert this density into kilograms
tamaranim1 [39]

Density is given as

\rho = 5.23 * 10^{-6} kg/mm^3

now we have to convert this density into kg/m^3

now we have

1 m = 1000 mm

\rho = 5.23 * 10^{-6} \frac{kg}{(1*10^-3 m)^3}

\rho = 5.23 * 10^{-6} \frac{1*10^9 kg}{m^3}

\rho = 5.23 * 10^3 kg/m^3

\rho = 5230 kg/m^3

8 0
3 years ago
a car is going around a roundabout.explain why we say that it is accelerating even if it is moving at a constant speed.
kiruha [24]

Because 'acceleration' does NOT mean 'speeding up'. 
It means ANY change in motion ... speeding up, slowing down,
or changing DIRECTION.

When traveling a roundabout, or any curved path, the direction
is constantly changing even if the speed is constant, so there is
constant acceleration going on.

4 0
3 years ago
In order to increase the speed in a gear system
Ludmilka [50]

Answer:

the driving gear must be larger than the driven gear

Explanation:

6 0
2 years ago
A body starts with a velocity of 20 m/s, accelerates uniformly for a time t, moves with constant velocity for the same time, and
Bezzdna [24]

Answer:

t=0.14s

Explanation:

  • t=
  • <em><u>\frac{s}{v}</u></em>
  • <em><u>t</u></em><em><u>=</u></em>
  • <em><u>\frac{20}{140}</u></em>
  • <em><u>Where</u></em><em><u> </u></em><em><u>s</u></em><em><u>=</u></em><em><u> </u></em><em><u>speed</u></em>
  • <em><u>V</u></em><em><u>=</u></em><em><u>distance</u></em><em><u> </u></em>
  • <em><u>And</u></em><em><u> </u></em><em><u>t</u></em><em><u>=</u></em><em><u>time</u></em><em><u> </u></em>
7 0
3 years ago
Monochromatic electromagnetic radiation illuminates an area of a surface. The electric and magnetic fields of the waves are then
emmasim [6.3K]

Answer:

c) True. factor four

Explanation:

The energy density of an electromagnetic wave is given by

             u = ½ ε₀ E² = B² / 2μ₀

Where ε₀ is the dielectric constant and μ₀ the magnetic permittivity.

Let's apply this equation to the present case

 

If we double the electro field

               E ’= 2 E₀

               u’= ½  ε₀ (2E₀)²

               u’= ½ ε₀ Eo² 4

               u’= 4 u₀

Therefore the energy is multiplied by four

Let's check the answers

a) False

b) False

c) True

d) False

e) False

6 0
3 years ago
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