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Fofino [41]
3 years ago
11

Which statement explains which component is likely to be more powerful in explaining a scientific phenomenon? (4 points)

Chemistry
1 answer:
icang [17]3 years ago
3 0

Answer: option three

Explanation:

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Answer:

An amide may be produced by reacting an acid chloride with ammonia.

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Beryllium, magnesium and calcium all are located in the alkaline earth group. Which of these characteristics do these elements h
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They each have similar density
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Which of the following is not a factor that affects thermal energy of a substance?
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The answer is : B. age of material

thermal Energy is an energy that come from heat, which caused by the movement of the particles in that substance. The faster it moves, the more energy it produced, which is affected by the change of temperature, its composition, and its size
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Use logarithmic properties to solve the following equation log3 5x+ log3 7= 4 leave your answer in fraction form please
Salsk061 [2.6K]

Explanation:

Adding logs of same base is equivalent to multiplying the arguments. You get:

log_{3}(35x)  = 4

Use the definition of the log to turn this into an exponential function:

{3}^{4}  = 35x

81 = 35x

x =  \frac{81}{35}

5 0
2 years ago
A container of N2O3(g) has a pressure of 0.265 atm. When the absolute temperature of the N2O3(g) is tripled, the gas completely
Rzqust [24]

Answer:

1.59 atm

Explanation:

The reaction is:

N_{2}O_{3}(g) - - -> NO_{2}(g)+NO(g)

The dalton's law tell us that the total pressure of a mixture of gases is the sum of the partial pressure of every gas.

So after the reaction the total pressure is:

P_{total}=P_{NO_{2}}+P_{NO}

we don't include N_{2}O_{3} because it decomposed completely.

Assuming  ideal gases

PV=nRT

P= pressure, V= volume of the container, n= mol of gas, R=constant of gases and T=temperature.

so moles of N_{2}O_{3} is:

n_{N_{2}O_{3}}=\frac{P_{1}V}{RT_{1}}

from the  reaction stoichiometry (1:1) we have that after the reaction the number of moles of each product is the same number of moles of N_{2}O_{3}.

n_{NO_{2}}=\frac{P_{1}V}{RT_{1}}

n_{NO}=\frac{P_{1}V}{RT_{1}}

The partial pressure of each gas is:

P_{NO_{2}}=\frac{n_{NO_{2}*R*T_{2}}}{V}

P_{NO}=\frac{n_{NO}*R*T_{2}}{V}

so total pressure is:

P_{total}=(n_{NO_{2}}+n_{NO})*\frac{R*T_{2}}{V}

replacing the moles we get:

P_{total}=(2*\frac{P_{1}V}{RT_{1}})*\frac{R*T_{2}}{V}

We know that T2=3*T1

replacing this value in the equation we get:

P_{total}=2*\frac{P_{1}V}{RT_{1}}*\frac{R*3T_{1}}{V}

P_{total}=6*P_{1} = 6*0.265 atm = 1.59 atm

5 0
3 years ago
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