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Over [174]
3 years ago
14

PLEASEE!! I NEED HELPP!! What is true in a boom-bust cycle? When the number of plants decreases, the number of animals decreases

. When the number of plants decreases, the number of animals remains the same. When the number of plants increases, the number of animals remains the same.
Mathematics
1 answer:
alex41 [277]3 years ago
6 0

Answer:

The answer is when the number of plants decreases, the number of animals decreases. Because if you take away plants, then what will the animals eat. All of the herbivores will die, then the carnivores because they have to animals to eat.

Step-by-step explanation:

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What is the area of a sector with a central angle 210 and a diameter of 4.6
gizmo_the_mogwai [7]
Theta = 210°
r = 4.6/2 = 2.3
Area of circle = pi * r * r
= 3.14 * 2.3 * 2.3 = 16.61
Area of sector =
(theta / 360) * area of circle
= (210/360) * 16.61
= 9.69
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3 years ago
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How do you solve k/2+9=30
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If you would like to solve the equation k / 2 + 9 = 30, you can calculate this using the following steps:

k / 2 + 9 = 30
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3 years ago
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Rewrite the system of linear equations as a matrix equation AX = B.
iren2701 [21]

Answer:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

Eq. 1 : x1 + 2x2 + 5x3 = 5

Eq. 2 : x1 + x2 + x3 = 6

E1. 3 : 4x1 + 6x2 + 5x3 = 7

Coefficients for x1 ; x2 ; x3

From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]

And the vector of vriables (X) is:

\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

In conclusion, AX=B is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

7 0
3 years ago
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Nikitich [7]

Answer:

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Answer:

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