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3 years ago

Pleasee help anyone please

Mathematics

2 answers:

Yakvenalex [24]3 years ago

8 0

Answer:

x = 6

Step-by-step explanation:

72 + 64 + (4x + 20) = 180

4x + 156 = 180

4x = 180 - 156

4x = 24

x = 6

iris [78.8K]3 years ago

3 0

Answer:

x must be 14/4 = 7/2

Step-by-step explanation:

The sum of the three interior angles of a triangle must be 180 degrees.

Thus, in this particular case,

82 + 64 + 4x + 20 = 180, or

146 + 4x = 160, or

4x = 160 - 146 = 14

Then 4x = 14, and x must be 14/4 = 7/2

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What is 140/180 as a decimal

Naddika [18.5K]

I think the answer is 0.8 or 0.78.
You divide 140/180 which gives you 0.77777778
You can either round up to the nearest hundredth or tenth.

7 0

3 years ago

Please answer asap!!

jonny [76]

-3x(-7) = -3(-2)(-7) ⇒ -42

-42 would be the answer.

4 0

3 years ago

Read 2 more answers

Find the Volume. Use pi=3.14. Round to the nearest hundredth.

aleksandr82 [10.1K]

<h2>Volume = 4.19 inches³</h2>

<u>Step-by-step explanation:</u>

radius = 1 inches

π = 3.14

volume of SPHERE = 4/3 × π × radius³

= 4/3 × 3.14 × 1³

= 4.19 inches³

4 0

3 years ago

3. Galshore of Maloat is making a journey from the island of Gont to Oranea. The distance from the two lands is 965 miles. Galsh

USPshnik [31]

Answer:

3. about 7.48 hours

4. about 1.8892 hours

Step-by-step explanation:

Both of these questions make use of the relation ...

time = distance / speed

3. time = (965 mi)/(129 mi/h) ≈ 7.48062 h ≈ 7.48 h

4. time = (612.1 mi)/(324 mi/h) ≈ 1.889198 h ≈ 1.8892 h

(We have rounded the time to sufficient precision so that the distance at the given speed rounds to the number given.)

3 0

3 years ago

3. The adult men of the Dinaric Alps have the highest average height of all regions. The

ahrayia [7]

Using the normal distribution, it is found that:

3 - a) The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

3 - b) The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.

4 - a) The 25th percentile for the math scores was of 71.6 inches.

4 - b) The 75th percentile for the math scores was of 78.4 inches.

<h3>Normal Probability Distribution </h3>

In a <em>normal distribution </em>with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

Question 3:

The mean is of 73 inches, hence $\mu = 73$ .

The standard deviation is of 3 inches, hence $\sigma = 3$ .

Item a:

The 40th percentile is X when Z has a p-value of 0.4, so <u>X when Z = -0.253</u>.

$Z = \frac{X - \mu}{\sigma}$

$-0.253 = \frac{X - 73}{3}$

$X - 73 = -0.253(3)$

$X = 72.2$

The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

Item b:

The minimum height is the 100 - 10 = 90th percentile is X when Z has a p-value of 0.9, so <u>X when Z = 1.28</u>.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 73}{3}$

$X - 73 = 1.28(3)$

$X = 76.84$

The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.

Question 4:

The mean score is of 75, hence $\mu = 75$ .

The standard deviation is of 5, hence $\sigma = 5$ .

Item a:

The 25th percentile is X when Z has a p-value of 0.25, so <u>X when Z = -0.675</u>.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 75}{5}$

$X - 75 = -0.675(5)$

$X = 71.6$

The 25th percentile for the math scores was of 71.6 inches.

Item b:

The 75th percentile is X when Z has a p-value of 0.25, so <u>X when Z = 0.675</u>.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 75}{5}$

$X - 75 = 0.675(5)$

$X = 78.4$

The 75th percentile for the math scores was of 78.4 inches.

To learn more about the normal distribution, you can take a look at brainly.com/question/24663213

5 0

2 years ago