A rational
B Irrational
C Irrational
~ThePirc
Answer:
The short answer is there isn’t.
Start by writing each of these as an expression:
x * y = 60
x + y = 7
Next, solve each for the same variable; in this case, y:
(x * y) / x = 60 / x
.: y = 60 / x
(x + y) - x = 7 - x
.: y = 7 - x
Next, replace y of the second expression to the first
y = 60 / x & y = 7 - x
.: 7 - x = 60 / x
Now, solve for x:
(7 - x) * x = (60 / x) * x
.: x * 7 - x^2 = 60
This is quadratic, so write it in the form of ax2 + bx + x = 0
(-1)x^2 + (7)x + (-60) = 0
.: a = -1, b = 7, c = -60
Finally solve for b:
x = (-b +- sqrt(b^2 - 4*a*c)) / 2a
.: x = (-7 +- sqrt(7^2 - 4*-1*-60)) / (2 * -1)
.: x = (-7 +- sqrt(49 - 240)) / -2
.: x = (-7 +- sqrt(-191)) / -2
The square root of a negative value is imaginary and thus there’s no real answer to this problem.
Answer:
y=-3x+4
Step-by-step explanation:
im assuming that you need the equation of the table
to find slope, y2-y1/x2-x1 10-4/-2-0
6/-2=-3 slope=-3
y=mx+b just sub in the numbers from a point in the table
10=-3(-2)+b
10=6+b
b=4
y=-3x+b
Answer:
1
Step-by-step explanation:
it is 6/6
if it is right brainliest pls thanks
A) 2x +3
Plug in the x
2(4.1) + 3
8.2+ 3= 11.2
A is 11.2
B) 16-5y
Plug in the y
16 - 5(2.3)
16- 11.5= 4.5
B is 4.5
C) x+y
Plug in x and y
4.1 + 2.3= 6.4
C is 6.4
