3 years ago

What is the standard-form equation of the ellipse shown?

1 answer:

3 0

Hello,

(x/6)²+(y/5)²=1
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jeyben [28]

Answer:

8 ft^2

Step-by-step explanation:

$\frac{h1}{2ft} =\frac{h2}{3ft} \\\\$

area of ABC is:

$A= \frac{(3ft)(h2)}{2}$

area of ABC is 18 square ft, then

$h2 = \frac{(area)(2)}{3ft} = \frac{(18 ft^2)(2)}{3ft} =12ft$

now you can find h1 and the area for EFG

6 0

3 years ago

nika2105 [10]

Answer:

idk

Step-by-step explanation:

8 0

3 years ago

stepan [7]

(-a^3b^2*-a^-2b^-3)^-2/2a^2b^-3 = a^4b^9/2a^8b^4 =b^5/2a^4 so your answer is b^5/2a^4

7 0

3 years ago

Mademuasel [1]

No they’re not equivalent because 4(t+12) =68 and 4t+12=32

7 0

3 years ago

Sloan [31]

4x + 15 = 6x - 1
x = 8
m∠JLC = 47°

3 0

3 years ago