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3 years ago

The standard deviations of four data sets are shown in the table below. Which

Mathematics

1 answer:

seropon [69]3 years ago

4 0

You are correct. The higher the standard deviation is, the more spread out the data set will be. Nice work.

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Help ASAP!!<br><br> Worth 40 points!!!

Vlad1618 [11]

12 x g + 1
Hope this help you

7 0

3 years ago

Read 2 more answers

One can convert temperature from Fahrenheit into Newton using the formula N=11/60(F-32) . What is the temperature in Fahrenheit

Rasek [7]

We are given

$N=\frac{11}{60} (F-32)$

Since, we have to solve for F

so, we will isolate F on anyone side

step-1:

Multiply both sides by 60

$60\times N=60\times \frac{11}{60} (F-32)$

$60N=11 (F-32)$

step-2:

Divide both sides by 11

$\frac{60N}{11} =\frac{11(F-32)}{11}$

$\frac{60}{11}N =F-32$

step-3:

Add both sides by 32

$\frac{60}{11}N+32 =F-32+32$

$\frac{60}{11}N+32 =F$

so, we get

$F=\frac{60}{11}N+32$ ................Answer

5 0

2 years ago

A company manufactures a 14-ounce box of cereal. Boxes are randomly weighed to ensure the correct amount. If the discrepancy in

Stolb23 [73]

Answer:

Answer is B on Edge

F(x)=14-x

Step-by-step explanation:

8 0

3 years ago

An ostrich that is 63 inches tall is 17 inches taller than 2 times the height of a kiwi.

DerKrebs [107]

Answer:

The kiwi is 23 inches tall.

Step-by-step explanation:

63= 2k + 17

46= 2k

k= 23 inches tall

8 0

2 years ago

Wewaii [24]

Answer:

For covering $1$ unit area of the entire playground, the amount of sand required is equal to volume of $3$ buckets of sand.

Step-by-step explanation:

Given -

$\frac{1}{3}$ volume of sand in bucket is able to cover $\frac{1}{9}$ area of the entire playground

Thus,

For covering $\frac{1}{9}$ unit area of the entire playground, the amount of sand required is equal to $\frac{1}{3}$ of the total volume of sand in bucket

For covering $1$ unit area of the entire playground, the amount of sand required is equal to

$\frac{\frac{1}{3} }{\frac{1}{9} } \\\\\frac{1}{3} * \frac{9}{1} \\\frac{9}{3}\\= 3$

For covering $1$ unit area of the entire playground, the amount of sand required is equal to volume of $3$ buckets of sand.

4 0

2 years ago