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2 years ago

How to find the area of a triangle with a base of 4 1/2 and a height of 2 2/3

Mathematics

2 answers:

Ivahew [28]2 years ago

7 0

Answer:

Step-by-step explanation:

The formula for the area of a triangle is 1/2(bh).

4 1/2=9/2, 2 2/3= 8/3

9/2x8/3=72/6,

Kryger [21]2 years ago

6 0

Answer:

Step-by-step explanation:

The formula for the area of a triangle is 1/2(bh).

4 1/2=9/2, 2 2/3= 8/3

9/2x8/3=72/6,

12. However, you still have to divide by two, which gets you 6

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What is 3/6 plus 1/3

aksik [14]

Answer:

5/6

Step-by-step explanation:

3/6 + 1/3 = 3/6 + 2/6 = 5/6

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3 years ago

Read 2 more answers

The area of the parallelogram is 273 square units. What is the height of the parallelogram? ____units

Alex17521 [72]

Answer:

h = 13 units²

Step-by-step explanation:

The way to find the area of a parallelogram is to multiply the length of one side (21) and multiply it by the height:

A = l*h

We know the area and the length:

273 = 21*h

Now we solve for height.

273/21 = (21*h)/21

273/21 = h

273/21 = 13

h = 13 units²

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3 years ago

Chelsea has 11 times as many art brushes as Monique. If they have 60 art brushes altogether, how many brushes does chelsea have

Keith_Richards [23]

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3 years ago

Paula walks 1/12 mile in 5/3 minutes. What rate is equivalent to the rate she walked?

mel-nik [20]

The rate that is equivalent to the rate Paula walked is 1/20 mile/minute OR 0.05 mile/minute

<h3>Calculating Rate </h3>

From the question, we are to determine the rate which is equivalent to the rate Paula walked

Using the formula,

$Rate = \frac{Distance}{Time}$

From the given information,

Distance = 1/12 mile

Time = 5/3 minutes

Putting the parameters into the formula, we get

$Rate =\frac{\frac{1}{12} }{\frac{5}{3} }$

$Rate = \frac{1}{12} \div \frac{5}{3}$

$Rate = \frac{1}{12} \times \frac{3}{5}$

$Rate = \frac{3}{60}$

$Rate = \frac{1}{20}$ mile/minute

Hence, the rate that is equivalent to the rate Paula walked is 1/20 mile/minute OR 0.05 mile/minute

Learn more on Calculating Rate here: brainly.com/question/21208007

#SPJ 1

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2 years ago

How do I solve these measurement problems?

Natalka [10]

You can either try it with a ruler or a long rules probably the long ruler for the bigger numbers. But either could be good

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3 years ago