Answer:
r=16
Step-by-step explanation:
2r = 37-5
2r = 32
r = 16
Answer:
1700
Step-by-step explanation:
the answer is on the other answer
mark pls
Problem 1
With limits, you are looking to see what happens when x gets closer to some value. For example, as x gets closer to x = 2 (from the left and right side), then y is getting closer and closer to y = 1/2. Therefore the limiting value is 1/2
Another example: as x gets closer to x = 4 from the right hand side, the y value gets closer to y = 4. This y value is different if you approach x = 0 from the left side (y would approach y = 1/2)
Use examples like this and you'll get the results you see in "figure 1"
For any function values, you'll look for actual points on the graph. A point does not exist if there is an open circle. There is an open circle at x = 2 for instance, so that's why f(2) = UND. On the other hand, f(0) is defined and it is equal to 4 as the point (0,4) is on the function curve.
=======================================================
Problem 2
This is basically an extension of problem 1. The same idea applies. See "figure 2" (in the attached images) for the answers.
Answer:
(x-3)(x-9)
Step-by-step explanation:
first thing you need to do is move the -6 over. so we're going to add 6 to both sides (we add because it's negative 6 and we need 0 on the right side)
so you have: x^2-12x+27
now we need to come up with two numbers that add to -12 and multiply to 27.
the factors of 27 are 9 & 3 and 27 & 1. only 9 & 3 add to 12 so we are going to use those.
since the 12 is negative however, 9 and 3 should both be negative.
therefore we get: (x-3)(x-9)
*it doesn't matter which order you put them in!