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nlexa [21]
3 years ago
7

Identify the power of ten that defines each of these prefixes. Input your answers as 10 x where x is the power of ten. nano- ___

____________. kilo- _______________. centi- _______________. micro- _______________. milli- _______________. mega- _______________.
Chemistry
1 answer:
Gemiola [76]3 years ago
7 0

<u>Answer:</u> The quantity of every prefix is written below as a power of ten.

<u>Explanation:</u>

In the metric system of measurement, the name of multiples and subdivision of any unit is done by combining the name of the unit with the prefixes.

<u>For Example:</u> deka, hecto and kilo means 10, 100 and 1000 respectively. Deci, centi and milli means one-tenth, one-hundredth, and one-thousandth respectively.

The quantity of these prefixes are written as the power of 10.

For the given prefixes:

<u>Nano:</u>  The quantity will be 10^{-9}

<u>Kilo:</u>  The quantity will be 10^3

<u>Centi:</u>  The quantity will be 10^{-2}

<u>Micro:</u>  The quantity will be 10^{-6}

<u>Milli:</u>  The quantity will be 10^{-3}

<u>Mega:</u>  The quantity will be 10^6

Hence, the quantity of every prefix is written above as a power of ten.

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Answer:

0.12M

Explanation:

A balanced equation for the reaction will go a great deal in obtaining our desired result. So, let us write a balanced equation for the reaction

HCl + NaOH —> NaCl + H2O

From the above equation,

nA (mole of the acid) = 1

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Data obtained from the question include:

Vb (volume of the base) = 30mL

Mb (Molarity of the base) = 0.1M

Va (volume of the acid) = 25mL

Ma (Molarity of the acid) =?

The molarity of the acid can be obtained as follow:

MaVa/MbVb = nA/nB

Ma x 25/ 0.1 x 30 = 1

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Divide both side by 25

Ma = (0.1 x 30) / 25

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What is the hydroxide-ion concentration in a solution formed by combining 200. ml of 0.16 m hcl with 300. ml of 0.091 m naoh at
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A very simple assumption for the specific heat of a crystalline solid is that each vibrational mode of the solid acts independen
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Answer:

4.7 kJ/kmol-K

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Using the Debye model the specific heat capacity in kJ/kmol-K

c = 12π⁴Nk(T/θ)³/5

where N = avogadro's number = 6.02 × 10²³ mol⁻¹, k = 1.38 × 10⁻²³ JK⁻¹, T = room temperature = 298 K and θ = Debye temperature = 2219 K  

Substituting these values into c we have

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