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EastWind [94]
2 years ago
12

Although cannabinol and methyl alcohol are both alcohols, cannabinol is very slightly soluble in methyl alcohol at room temperat

ure. Explain.
Chemistry
2 answers:
xxMikexx [17]2 years ago
8 0

Cannabinol is a psychoactive cannabinoid that is found in trace amounts in Cannabis. This is most often found in aged Cannabis. Oxidized cannabis products and traditionally produced hashish are high in cannabinol. Cannabinol is slightly soluble in methyl alcohol at room temperature. This is because it is not very polar (two non-polar rings and one polar ring) and is solid at room temperature.

olganol [36]2 years ago
5 0

Hey there!:

It is a solid at room temperature.

Take a look at the structure of the compound. It has 3 rings total, two of which are phenyl rings, 3 methyl groups and a pentyl group while there is only one OH. That is a lot of non-polar groups for just one polar group. This is why it is sparingly soluble in MeOH at RT, it really is not a very polar molecule (the general rule of thumb is 5 C's for every polar group for the molecular to be considered polar, this of course is a generalization).

I hope that helps.

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Which of the following is a property of matter?
lana66690 [7]

Explanation:

Matter also exhibits physical properties. Physical properties are used to observe and describe matter. Physical properties can be observed or measured without changing the composition of matter. These are properties such as mass, weight, volume, and density.

5 0
2 years ago
Suppose the gas resulting from the sublimation of 1.00 g carbon dioxide is collected over water at 25.0◦c into a 1.00 l containe
jeyben [28]

Answer:

0.55 atm

Explanation:

First of all, we need to calculate the number of moles corresponding to 1.00 g of carbon dioxide. This is given by

n=\frac{m}{M_m}

where

m = 1.00 g is the mass of the gas

Mm = 44.0 g/mol is the molar mass of the gas

Substituting,

n=\frac{1.00 g}{44.0 g/mol}=0.0227 mol

Now we can find the pressure of the gas by using the ideal gas law:

pV=nRT

where

p is the gas pressure

V = 1.00 L is the volume

n = 0.0227 mol is the number of moles

R = 0.082 L/(atm K mol) is the gas constant

T = 25.0 C + 273 = 298 K is the temperature of the gas

Solving the formula for p, we find

p=\frac{nRT}{V}=\frac{(0.0227 mol)(0.082 L/(atm K mol))(298 K)}{1.00 L}=0.55 atm

8 0
3 years ago
Electricity is the _of charged<br> particles.<br> A.movement<br> B. collection<br> C.build up
Vitek1552 [10]

Answer:

c

Explanation:

4 0
3 years ago
4. Quando se obtém a potência máxima da célula, o valor indicado no amperímetro, na unidade SI, está no intervalo: (A) [3,1; 3,2
Annette [7]

Answer:i dont speak english

Explanation:

sorry

8 0
2 years ago
A solution is created by dissolving 13.5 grams of ammonium chloride in enough water to make 235 ml of solution. how many moles o
erica [24]
<span>Moles = 0.252 Molarity = 1.07 This question is badly worded. You're asking for moles and I suspect you really want molarity. The number of moles of ammonium chloride you have in the solution will remain constant regardless of the volume of the solution. However, the molarity of the solution will differ depending upon how concentrated it is. So I'll give you both the number of moles of ammonium chloride you have, and the molarity of the resulting solution. Please talk to your teacher if you're confused by the difference between moles and molarity. The formula for ammonium chloride is NH4Cl. So let's calculate it's molar mass. Start by looking up the associated atomic weights. Atomic weight nitrogen = 14.0067 Atomic weight hydrogen = 1.00794 Atomic weight chlorine = 35.453 Molar mass NH4Cl = 14.0067 + 4 * 1.00794 + 35.453 = 53.49146 g/mol Moles NH4Cl = 13.5 g / 53.49146 g/mol = 0.252376735 mol Molarity is defined as moles per liter, so let's divide the number of moles we have by the volume in liters. So: 0.252376735 mol / 0.235 l = 1.073943551 M Rounding to 3 significant figures gives: 0.252 moles, 1.07 molarity.</span>
7 0
3 years ago
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