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musickatia [10]
2 years ago
10

The process of splitting an atom into two lighter atoms is called

Chemistry
2 answers:
Temka [501]2 years ago
6 0

Answer is: C. nuclear fission.

Nuclear fission is a nuclear reaction or a radioactive decay where nucleus of atom split into smaller ligher nuclei.

Nuclear fission is exothermic reaction which release large amounts of energy (electromagnetic radiation or as kinetic energy, which heat reactors where fission reaction take place).

Varvara68 [4.7K]2 years ago
5 0

<u>Answer:</u> The process of splitting of an atom into two lighter atoms is called is called nuclear fission.

<u>Explanation:</u>

There are two types of nuclear decay reactions:

  • <u>Nuclear fission reactions:</u> They are defined as the reaction in which, the heavier atoms splits into two or more lighter atoms. The number of atoms formed in this reaction increases from the given atoms.
  • <u>Nuclear fusion reactions:</u> They are defined as the reaction in which, two or more lighter atoms combine to form a heavier atom. The number of atoms formed in this reaction decreases from the given atoms.

Hence, the process of splitting of an atom into two lighter atoms is called is called nuclear fission.

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56. What would be the valence electrons of 14Si, 16S, 32Ge respectively?
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For the following element, the valence electron can be noticed when we write the electronic configuration of each element.

Silicon =  1s2 2s2 2P6 3s2 3p2

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3 years ago
Which statement is true for the given reaction? Na2SO4(aq) + Mg(s) →
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The nucleus of isotope A of an element has a larger mass than isotope B of the same elemen
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2 years ago
Lt takes 4 hr 39 min for a 2.00-mg sample of radium-230 to decay to 0.25 mg. what is the half-life of radium-230?
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Radioactive decay => C = Co { e ^ (- kt) |

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Co = 2.00 mg
C = 0.25 mg
t = 4 hr 39 min

Time conversion: 4 hr 39 min = 4.65 hr

1) Replace the data in the equation to find k

C = Co { e ^ (-kt) } => C / Co = e ^ (-kt) => -kt = ln { C / Co} => kt = ln {Co / C}

=> k = ln {Co / C} / t =  ln {2.00mg / 0.25mg} / 4.65 hr = 0.44719

2) Use C / Co  = 1/2 to find the hallf-life

C / Co = e ^ (-kt) => -kt = ln (C / Co)

=> -kt = ln (1/2) => kt = ln(2) => t = ln (2) / k

t = ln(2) / 0.44719 = 1.55 hr.

Answer: 1.55 hr
6 0
3 years ago
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