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goldfiish [28.3K]
3 years ago
9

What's the midpoint between (1,-7) and (-1,-23)

Mathematics
1 answer:
Alik [6]3 years ago
8 0
Answer: (0,-15)

--------------------------------------------------

Explanation:

Add up the x coordinates to get 1+(-1) = 0. Divide this sum in half to get 0/2 = 0. Therefore the x coordinate of the midpoint is 0.

Repeat for the y coordinates. First add the y coordinates to get -7+(-23) = -30. Then divide that result in half to get -30/2 = -15. So the y coordinate of the midpoint is -15.

Overall, the midpoint is (0,-15).

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Plz help i need helppppppp
Goshia [24]

Answer:

1) 36

b) 5

c) 3.0

Step-by-step explanation:

1) The recursive formula that defines the given sequence is

a_1=12 \\  a_n=a_{n-1}+4.

That means we keep adding 4 to the subsequent terms:

The sequence will be:

12,16,20,24,28,32,36,...

Therefore the seventh term is 36.

2) The sequence is recursively defined by;

a_1=20\\  a_n=a_{n-1} - 5

This means, we have to keep subtracting 5 from the subsequent terms.

The sequence will be;

20,15,10,5,...

Therefore the fourth term is 5

3) The sequence is recursively defined by:

f(n+1)=f(n)+0.5

where f(1)=-1.5

This means that, the subsequent terms can be found by adding 0.5 to the previous terms.

The sequence will be:

-1.5,-1.0,-0.5,0,0.5,1,1.5,2.0,2.5,3.0,....

Therefore f(10)=3.0

8 0
3 years ago
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Roman55 [17]

Answer:

l and n are parallel

Step-by-step explanation:

360° around a point

65° x 2 = 130

360 - 130 = 230

230/2 = 115

115 ° are corresponding angles

3 0
3 years ago
What is the value of the expression?
gulaghasi [49]
The answer is fourteen
3 0
3 years ago
How do I write a recursive formula for this sequence? 2, 6, 18, 54, 162, ... I already know the common difference is x3.
dmitriy555 [2]
For the sequence 2, 6, 18, 54, ..., the explicit formula is: an = a1 ! rn"1 = 2 ! 3n"1 , and the recursive formula is: a1 = 2, an+1 = an ! 3 . In each case, successively replacing n by 1, 2, 3, ... will yield the terms of the sequence. See the examples below.
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Find all the zeros of the equation
lapo4ka [179]

Divide both sides by -3, and replace x^2 with y. Then

-3x^4+27x^2+1200=0\iff y^2-9y-400=0

Factorize the quadratic in y to get

y^2-9y-400=(y+16)(y-25)=0\implies y=-16,y=25

which in turn means

x^2=-16,x^2=25

But x^2\ge0 for all real x, so we can ignore the first solution. This leaves us with

x^2=25\implies x=\pm\sqrt{25}=\pm5

If we allow for any complex solution, then we can continue with the solution we ignored:

x^2=-16\implies x=\pm\sqrt{-16}=\pm i\sqrt{16}=\pm4i

6 0
3 years ago
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