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Gre4nikov [31]
3 years ago
11

Solve for 3a: 4a − 2 = a + 4 3a =

Mathematics
1 answer:
ziro4ka [17]3 years ago
8 0
4a-2=a+4
+2 to both sides
4a=a+6
-a from both sides
3a=6
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\boxed { \boxed { a_n = a_1 + d(n - 1)}}

a_{14} = -33 , a_{15} = 9,

a_{14} =  a_1 + d(14 - 1) = -33
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So the two equations:
a_1 + 13d = -33 ----------------- ( 1 )
a_1 + 14d = 9     ----------------- ( 2 )

(2) - (1) :
d = 42  ----------------- (Sub into 1)

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\boxed { \boxed { a_n = -578 + 42(n - 1)}}




3 0
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