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lina2011 [118]
3 years ago
6

Which number is a common factor of 64 and 100? A) 4 B) 8 C) 16 D) 20

Mathematics
2 answers:
antiseptic1488 [7]3 years ago
5 0

Answer:

4

Step-by-step explanation:

Karolina [17]3 years ago
3 0

Answer:

A) 4

Step-by-step explanation:

The factors of 64 are:

1, 2, 4, 8, 16, 32, 64

The factors of 100 are:

1, 2, 4, 5, 10, 20, 25, 50, 100

The common factors are:

1, 2, 4

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WINSTONCH [101]
Shape A is congruent to Shape B because If you were to rotate one of the two and flip it the would like up and match.
5 0
3 years ago
Please help :c
miss Akunina [59]

Answer: $17.55

Step-by-step explanation:

36 x 0.65 = $23.40 total for all cookies

($23.40/1) x (3/4) = (70.2/4)

70.2 divided by 4 = $17.55

or

$23.40 x .75 = $17.55

4 0
3 years ago
Y=-x^2+6x-4<br> Find the Axis of Symmetry and the Vertex, Also solve the whole equation.
Inessa [10]

Answer:

1. <em>Axis of symmetry</em>: x = 3

2. <em>Vertex:</em> (3,5)

3. <em>Solution of the equation</em>:

<u />

  • x-intercepts:

               (3-\sqrt{5},0) \\\\(3+\sqrt{5},0)

  • y-intercept: (0, -4)

Explanation:

<u>1. Equation:</u>

    y=-x^2+6x-4

<u>2. </u><em><u>Axis of symmetry:</u></em>

That is the equation of a parabola, whose standard form is:

                 y=ax^2+bx+c

Where:    

                 a=-1;b=6;c=-4

The axis of symmetry is the vertical line with equation:

               x=-b/2a

Substitute  a=-1,\text{ and }b=6

          x=-6/[(2)(-1)]=-6/(-2)=3

Thus, the axis of symmetry is:

            x=3

<em><u>3. Vertex</u></em>

<em><u /></em>

The x-coordinate of the vertex is equal to the axys of symmetry, i.e x = 3.

To find the y-xoordinate, substitute this value of x into the equation for y:

               y=-x^2+6x-4\\\\y=-(3)^2+6(3)-4=-9+18-4=5

Therefore, the vertex is (3, 5)

<u>4. Find the x-intercepts</u>

The x-intercepts are the roots of the equation, which are the points wher y = 0.

        y=-x^2+6x-4=0

Use the quadratic equation:

       x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} \\\\x=\frac{-6\pm\sqrt{(-6)^2-4(-1)(-4)} }{2(-1)}\\\\x_1=3-\sqrt{5} \\\\x_2=3+\sqrt{5}

<u>5. Find the y-intercept</u>

<u />

The y-intercet is the value of y when x=0:

         y=-x^2+6x-4\\\\y=-(0)^2+6(0)-4=-4

7 0
4 years ago
Which is a factor of 10x - 20x2 - 2x + 4?
sveta [45]
Add like terms and then simplify
7 0
3 years ago
Which of the following values in the set below will make the equation 2x + 1 = 3 true? (Only input the number.)
slava [35]
The only one that makes sense is 1
7 0
3 years ago
Read 2 more answers
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