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soldi70 [24.7K]
3 years ago
11

How many real-number solutions does the equation have?

Mathematics
2 answers:
earnstyle [38]3 years ago
7 0

Answer:

2

2Step-by-step explanation:

Dmitrij [34]3 years ago
6 0

Answer:

I'm guessing none because the discrimant (sqrt of b squared - 4ac is less than zero, signifying it has no real roots

Step-by-step explanation:

have a happy holidays!

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Why is it that -log(x+8)=4-log(x-7) has no solution? (they are log base 2)
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0=4-\log _{10}\left(x-7\right)+\log _{10}\left(x+8\right) 

0+\log _{10}\left(x-7\right)=4-\log _{10}\left(x-7\right)+\log _{10}\left(x+8\right)+\log _{10}\left(x-7\right) 

\log _{10}\left(x-7\right)=\log _{10}\left(x+8\right)+4 

\log _{10}\left(x-7\right)=\log _{10}\left(x+8\right)+\log _{10}\left(10000\right) 

x-7=\left(x+8\right)\cdot \:10000 

\mathrm{Solve\:}\:x-7=\left(x+8\right)10000:\quad x=-\dfrac{26669}{3333} 

\mathrm{Verifying\:Solutions}:\quad x=-\dfrac{26669}{3333}\space\mathrm{False} 

\mathrm{No\:Solution\:for\:x\in \mathbb{R}}
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