Answer:
Option C.
Step-by-step explanation:
It is given that planes A and B intersect in line s.
It means, all points lie on the line s must be lie on both plane A and B because s is the line of intersection of both plane A and B.
It is given that V is a point on line s.
Since, the point V lies on line s, therefore it is also lies on both plane A and B.
Hence, the correct option is C.
The answer to the given question is as below:-
Polynomials:-
x³-7x²+9x-5x⁴-20
x⁵-5x⁴+4x³+2x-1
3x²-5x⁴+2x-12
Non-polynomial:-
x⁻5-5x⁻⁴+4x⁻³+2x⁻1-1
![\dfrac{4}{x^4}+ \dfrac{3}{x^3}-\dfrac{2}{x^4}-1](https://tex.z-dn.net/?f=%5Cdfrac%7B4%7D%7Bx%5E4%7D%2B%20%5Cdfrac%7B3%7D%7Bx%5E3%7D-%5Cdfrac%7B2%7D%7Bx%5E4%7D-1)
![\sqrt[4]{x} -\sqrt[3]{x} 4+\sqrt{x}-8x+16](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%7D%20-%5Csqrt%5B3%5D%7Bx%7D%204%2B%5Csqrt%7Bx%7D-8x%2B16)
<h3>What are polynomials?</h3>
A polynomial is a mathematical equation made up of indeterminates and coefficients and involves only addition, subtraction, multiplication, and non-negative integer exponentiation of variables. The exponents of the polynomials can not be irrational.
So the table will be formed as:-
Polynomials:- Non-polynomial:-
x³-7x²+9x-5x⁴-20 x⁻5-5x⁻⁴+4x⁻³+2x⁻1-1
x⁵-5x⁴+4x³+2x-1 ![\dfrac{4}{x^4}+ \dfrac{3}{x^3}-\dfrac{2}{x^4}-1](https://tex.z-dn.net/?f=%5Cdfrac%7B4%7D%7Bx%5E4%7D%2B%20%5Cdfrac%7B3%7D%7Bx%5E3%7D-%5Cdfrac%7B2%7D%7Bx%5E4%7D-1)
3x²-5x⁴+2x-12 ![\sqrt[4]{x} -\sqrt[3]{x} 4+\sqrt{x}-8x+16](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%7D%20-%5Csqrt%5B3%5D%7Bx%7D%204%2B%5Csqrt%7Bx%7D-8x%2B16)
Therefore the polynomials and non-polynomials are shown in the table above.
To know more about polynomials follow
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Adults and children of all ages! In order to find the most accurate results, you need a larger sample space :)
One way to go about this is to first list everything we know in the form of variables. This will make it easier to see how these numbers correlate instead of trying to remember formulas to plug these numbers into.
TimeA = 2.4h (time of Car A to travel)
TimeB = 4h (time of Car B to travel)
SpeedA = SpeedB + 22mph (Speed of Car A<span>)
</span>SpeedB = SpeedA - 22mph (Speed of Car B<span>)
</span>Distance = x (the distance traveled by each car)
We are looking for SpeedA. How can we find this? Well, we know that speed multiplied by time is equal to distance, so let's start there.
SpeedA * 2.4h = x
<span>(SpeedB + 22mph) * 2.4h = x
</span>(2.4h * SpeedB) + 52.8miles = x
We also know that:
SpeedB * 4h = x
Since both of these equations are equal to x, we can combine them:
SpeedB * 4h = x = <span>(2.4h * SpeedB) + 52.8miles
</span>SpeedB * 4h = <span>(2.4h * SpeedB) + 52.8miles
</span>1.6h * Speed B = 52.8miles
SpeedB = 52.8/1.6 mph = 33 mph
<span>SpeedA = SpeedB + 22mph = 33mph + 22mph = 55mph
</span>
Therefore, Car A was traveling at 55mph.
Answer:
C) If the area of a square is an odd perfect square, the perimeter of the square will be even.
Step-by-step explanation:
Just did it on edge.