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atroni [7]
3 years ago
12

Find the slope of the line that goes through the given points (-1, 4), (5, 4)

Mathematics
2 answers:
Alexeev081 [22]3 years ago
6 0
Your line is horizontal (same y values) in horizontal lines, the slope is always 0, so, your slope is 0
Temka [501]3 years ago
4 0
The formula would be y₂-y₁ ÷ x₂-x₁
-1 :x₁
4 : y₁
                                            4-4/5-(-1)     = <u><em>0 </em></u>
5 : x₂
4 : y₂

0 is the slope
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Detroit received 8 over 5 inches of snow in the morning. The city recorded of an 3 over 5inch of snow in the evening. What was t
xenn [34]

Answer:

11/5 inches

Step-by-step explanation:

total snowfall for the day = snowfall in morning + snowfall in evening

= 8 over 5 + 3 over 5 (all in inches)

= 8/5 + 3/5 (all in inches)

Since the denominators are the same (5), we can simply add the numerators up while keeping the denominator

(8/5 + 3/5) inches= (8+3)/5 inches = 11/5 inches = total snowfall for the day

7 0
2 years ago
One eighth of Tony's books are mystery books. He has 3mystery books. How many books does tony have in all?
Anit [1.1K]
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8 0
3 years ago
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Determine the slope of the line that is perpendicular to the line y = -7x - 12.
Mnenie [13.5K]

Answer:

None of these answers are correct.

Step-by-step explanation:

Perpendicular lines have opposite and reciprocal slopes, which means that we take the slope and we flip it. After we've done that, we change the sign.

Since the original slope is -7, first we flip it and get -1/7. Now we change the sign and get 1/7. Therefore, the perpendicular slope of this line would be 1/7

4 0
3 years ago
What is four over five divided by two
Anastaziya [24]
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4 0
3 years ago
Proving the Parallelogram Diagonal Theorem
lora16 [44]

Answer:

The proof is given below.

Step-by-step explanation:

Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of parallelogram bisect each other.

In ΔACD and ΔBEC

AD=BC              (∵Opposite sides of parallelogram are equal)

∠DAC=∠BCE       (∵Alternate angles)

∠ADC=∠CBE        (∵Alternate angles)

By ASA rule, ΔACD≅ΔBEC

By CPCT(Corresponding Parts of Congruent triangles)

AE=EC and DE=EB

Hence, AE is conruent to CE and BE is congruent to DE


3 0
3 years ago
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