Question

Two sound waves (wave X and wave Y) are moving through a medium at the same speed. If wave X has a greater frequency than wave Y, then wave X
A. has a lower amplitude.

B. has a greater amplitude.

C. has a longer wavelength.

D. has a shorter wavelength.

Answer 1

Answer:

D. has a shorter wavelength.

Explanation:

Speed is the change of position with respect to time:

$v=\frac{\Delta x}{t}$

Time will be the period, since it is the time of a cycle in a periodic phenomena, like a wave. The change of position will be the distance between the two consecutive points at which a cycle repeats, this is called wavelenght.

$v=\frac{\lambda}{T}$

Frequency measure the number of repetitions per unit of time. Thus, is inverse to the period.

$T=\frac{1}{f}\\v=\lambda f$

As can be seen, if the speed is the same, a greater frequency less wavelength and vice versa.

Answer 2

Frequency has nothing to do with amplitue, although it is inversely (meaning as one increases the other decreases) related to wavelength. the greater the frequency, the shorter the wavelength, and the smaller the frequency the longer the wavelength. Since wave X has a gretaer frequency, it has a D. Shorter wavelength.