What type of plant boundary is associated with the formation of an ocean boundaries?

The most recent evidence supporting the theory of plate tectonics would include A) GPS monitoring of plate speeds and movements.

Whitepunk [10]

A) GPS monitoring of plate speeds and movements.

Explanation:

The most recent evidence supporting the theory of plate tectonics would be GPS monitoring of plate speeds and movements.

A GPS is a Global Positioning System made up of series of components.

Plate tectonics theory is the movement of the earth's lithosphere relative to one another.
The recent advances uses a GPS system to monitor real-time movement of the plates.
The GPS system is made up of a system of satellite in space that communicates real-times locations to sensors on the earth surface.
From the sensors, observatory stations can know and duly observe how plates are moving.

learn more:

Lithosphere brainly.com/question/9582362

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5 0

3 years ago

If a 2 kg block of aluminium (SHC: 921 J/kg°C) is heated from 20°C to 40°C, how much energy was transferred to it?

IRISSAK [1]

H = mc∆T

where, H=heat energy

c = SHC

H = 2*921*(40-20)

H = 36840J

H = 36.84KJ

The energy transferred to it is 36.84KJ

4 0

3 years ago

What kind of geologic feature do all earthquakes occur?

joja [24]

Coastal areas near water bodies like sea and oceans

8 0

3 years ago

Which action would increase the strength of the electric force between the ballon and the water

OLga [1]

Complete question is;

Which action would increase the strength of the electric force between the balloon and the water?

A. Holding a magnet near the stream of water

B. Holding the balloon closer to the stream of water

C. Holding a magnet near the balloon

D. Moving the balloon farther away from the stream of water

Answer:

B. Holding the balloon closer to the stream of water

Explanation:

When we take a charged balloon near water, what happens is that it makes electrons to be pushed away which in turn leaves the area to be positively charged. This area is now attracted to the balloon and thus the strength of the electric force between the balloon and the water is increased.

8 0

3 years ago

An unmarked police car traveling a constant 38.6 m/s is passed by a speeder traveling 53.4 m/s. Precisely 2.2 seconds after the

Juliette [100K]

Answer:

The unmarked police car needs approximately 71.082 seconds to overtake the speeder.

Explanation:

Let suppose that speeder travels at constant velocity, whereas the unmarked police car accelerates at constant rate. In this case, we need to determine the instant when the police car overtakes the speeder. First, we construct a system of equations:

Unmarked police car

$s = s_{o}+v_{o,P}\cdot (t-t') + \frac{1}{2}\cdot a\cdot (t-t')^{2}$ (1)

Speeder

$s = s_{o} + v_{o,S}\cdot t$ (2)

Where:

$s_{o}$ - Initial position, measured in meters.

$s$ - Final position, measured in meters.

$v_{o,P}$ , $v_{o,S}$ - Initial velocities of the unmarked police car and the speeder, measured in meters per second.

$a$ - Acceleration of the unmarked police car, measured in meters per square second.

$t$ - Time, measured in seconds.

$t'$ - Initial instant for the unmarked police car, measured in seconds.

By equalizing (1) and (2), we expand and simplify the resulting expression:

$v_{o,P}\cdot (t-t')+\frac{1}{2}\cdot a\cdot (t-t')^{2} = v_{o,S}\cdot t$

$v_{o,P}\cdot t -v_{o,P}\cdot t' +\frac{1}{2}\cdot a\cdot t^{2}-a\cdot t'\cdot t+\frac{1}{2}\cdot a\cdot t'^{2} = v_{o,S}\cdot t$

$\frac{1}{2}\cdot a\cdot t^{2}+[(v_{o,P}-v_{o,S})-a\cdot t']\cdot t -\left(v_{o,P}\cdot t'-\frac{1}{2}\cdot a\cdot t'^{2}\right) = 0$

If we know that $a = 1.6\,\frac{m}{s^{2}}$ , $v_{o,P} = 0\,\frac{m}{s}$ , $v_{o,S} = 53.4\,\frac{m}{s}$ and $t' = 2.2\,s$ , then we solve the resulting second order polynomial:

$0.8\cdot t^{2}-56.92\cdot t +3.872 = 0$ (3)

$t_{1} \approx 71.082\,s$ , $t_{2}\approx 0.068$

Please notice that second root is due to error margin for approximations in coefficients. The required solution is the first root.

The unmarked police car needs approximately 71.082 seconds to overtake the speeder.

3 0

3 years ago