what voltage would produce a current of 100A through an aluminum wire that has a resistance of 3.44x10^-4 ohm?

1 answer:

7 0

Voltage = Current x Resistance
Voltage(?) = 100 x 1.98x10^-4 ohms 

Voltage = Current x Resistance 
Voltage(?) = 250 x 2.09x10^-4 ohms 

Voltage = Current x Resistance 
Voltage(?) = 100 x 3.44x10^-4 ohms

You might be interested in

Airbrakes on some trucks have how many second lag time with for the engage properly?

olga2289 [7]

The answer that best completes the given statement above is ONE SECOND (1). There should only be one second of lag time to engage properly for some of the airbrakes of the trucks. One half to one second is the normal lag time and it should not exceed beyond this time. Hope this helps.

6 0

2 years ago

The main light gathering device of a refractor telescope is

Nataly [62]

It's the "objective" lens ... the big one in the front.

3 0

2 years ago

A rocket is fired at 100 m/s at an angle of 37, what was its speed at the top of its path?

Nadusha1986 [10]

Answer:

0m/s

Explanation:

Since its fired at an angle, at the top there will be a split second where the velocity will be 0, as it has a parabolic shape, so the speed at the top of its path is 0

4 0

2 years ago

CAN SOMEONE PLEASE HELP ME WITH MY PHYSICS QUESTIONS? I NEED CORRECT ANSWERS ONLY!

BARSIC [14]

<h2>Right answer: acceleration due to gravity is always the same </h2><h2 />

According to the experiments done and currently verified, in vacuum (this means there is not air or any fluid), all objects in free fall experience the same acceleration, which is the acceleration of gravity.

Now, in this case we are on Earth, so the gravity value is $9.8\frac{m}{s^{2}}$

Note the objects experience the acceleration of gravity regardless of their mass.

Nevertheless, on Earth we have air, hence air resistance, so the afirmation "Free fall is a situation in which the only force acting upon an object is gravity" is not completely true on Earth, unless the following condition is fulfiled:

If the air resistance is too small that we can approximate it to zero in the calculations, then in free fall the objects will accelerate downwards at $9.8\frac{m}{s^{2}}$ and hit the ground at approximately the same time.