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Marizza181 [45]
3 years ago
9

A double-slit experiment is set up using red light (λ = 706 nm). A first order bright fringe is seen at a given location on a sc

reen. What wavelength of visible light (between 380 nm and 750 nm) would produce a dark fringe at the identical location on the screen? λ =
Physics
1 answer:
Elanso [62]3 years ago
6 0

Answer:

λ = 470.66 nm

Explanation:

for bright fringey_m = \frac{m\lambda D}{d}

D= distance between slit and screen

d= distance between the slits

for first order bright fringe m = 1,

        y_1 = \frac{1\lambda D}{d}

         y_1 = {706*D}{d}

for dark fringe,we have

y_m = {(m + 1/2)\lambda D}{d}    

Now to get the dark fringes at the same location we should have;

(706)D/d = (m + 1/2)λD/d    

put m = 1

(1 + 1/2)λ = (706)

λ = 470.66 nm

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Answer:

t=2.51min

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Answer:

<u>For M84:</u>

M = 590.7 * 10³⁶ kg

<u>For M87:</u>

M = 2307.46 * 10³⁶ kg

Explanation:

1 parsec, pc  = 3.08 * 10¹⁶ m

The equation of the orbit speed can be used to calculate the doppler velocity:

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making m the subject of the formula in the equation above to calculate the mass of the black hole:

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M = \frac{( 5*10^{5}) ^{2} *61.6* 10^{16} }{6.674 * 10^{-11} }

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The mass of the black hole in the galaxies is measured using the doppler shift.

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