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Marizza181 [45]
4 years ago
9

A double-slit experiment is set up using red light (λ = 706 nm). A first order bright fringe is seen at a given location on a sc

reen. What wavelength of visible light (between 380 nm and 750 nm) would produce a dark fringe at the identical location on the screen? λ =
Physics
1 answer:
Elanso [62]4 years ago
6 0

Answer:

λ = 470.66 nm

Explanation:

for bright fringey_m = \frac{m\lambda D}{d}

D= distance between slit and screen

d= distance between the slits

for first order bright fringe m = 1,

        y_1 = \frac{1\lambda D}{d}

         y_1 = {706*D}{d}

for dark fringe,we have

y_m = {(m + 1/2)\lambda D}{d}    

Now to get the dark fringes at the same location we should have;

(706)D/d = (m + 1/2)λD/d    

put m = 1

(1 + 1/2)λ = (706)

λ = 470.66 nm

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An student dropped their book from the top of a canyon into a river 40 meters below.
kotykmax [81]

Use this formula for an object starting from rest and accelerating:

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7 0
4 years ago
A 3" diameter germanium wafer that is 0.020" thick at 300K has 1.015 x 10^17 As atoms added to it. What is the resistivity of th
Ber [7]

Answer:

0.546 ohm / μm

Explanation:

Given that :

N = 1.015 * 10^17

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Hole mobility, h = 1900

Ng = 4.42 x10^22

q = 1.6*10^-19

Resistivity = 1/qNu

Resistivsity (R) = 1/(1.6*10^-19 * 1.015 * 10^17 * 3900)

= 0.01578880889 ohm /cm

Resistivity of germanium :

R = 1 / 2q * sqrt(Ng) * sqrt(u*h)

R = 1 / 2 * 1.6*10^-19 * sqrt(4.42 x10^22) * sqrt(3900*1900)

R = 1 /0.0001831

R = 5461.4964 ohm /cm

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0.546 ohm / μm

7 0
3 years ago
Please Help!!! It's for a quiz!!
Sphinxa [80]

Answer:

38.8 m/s

Explanation:

Force F(x) = 6 - 2x + 6x²

work

W=\displaystyle\int_{0}^{13.9}F(x)dx=\displaystyle\int_{0}^{13.9}(6-2x+6x^2)dx

=6x-x^2+2x^3|_{0}^{13.9}\\=5261 J

W = mv²/2=7v²/2 = 3.5v² = 5261

v = 38.8 m/s

3 0
2 years ago
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