A
d
b
b
a
c
c
c
a
b
a
b
d
d
a,c
100% 15/15 I promise these are the right answers
Answer:
Option C. 16.6 m/s
Explanation:
To round this 16.558 m/s to 3sf, we need to count the number beginning from 1. When we get to the 3rd number( ie 5), we'll examine the fourth number(i.e 5)to see if it less than five or greater. If it less than five, then we'll discard it. But if it five or greater, we'll approximate it and add it to the 3rd number.
So.
16.558 m/s = 16.6m/s to 3sf
Answer:
The acceleration of the collar is 10 m/s²
Explanation:
Given;
mass of the collar, m = 1 kg
applied force on the bar, F = 10 N
The acceleration of the collar can be calculated by applying Newton's second law of motion;
F = ma
where;
F is the applied force
m is mass of the object
a is the acceleration
a = F / m
a = 10 / 1
a = 10 m/s²
Therefore, the acceleration of the collar is 10 m/s²
Answer:
0.82 MPa
Explanation:
the change in pressure 'σ'=160kPa
K= σ/∈
=> σ/3∈
K= 160/(3 x 0.065)
K=820 kPA=0.82 MPa
Thus,the bulk modulus of the tissue 'K' is 0.82 MPa
