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Sonbull [250]
3 years ago
10

The funtions F and G are defined as follows

Mathematics
1 answer:
Vilka [71]3 years ago
3 0

Answer:

two functions f & g, then for all values of x for which both f(x) and g(x) are defined, the functions f + g, f-g, fg, and f/g are defined as follows.

Sum: Add the LIKE terms

Difference: Subtract the LIKE terms

Product: Distribute or FOIL

Quotient: Set up a fraction, then STOP - (Always state that the denominator ≠ 0)

Step-by-step explanation:

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A rectangular shelf has an area of 40 square inches. Its perimeter is 28 inches. What are the dimensions of the shelf?
Reptile [31]

Answer:

4 by 10

Step-by-step explanation:

4 times 10 is 40 (length times width)

4+4+10+20=28

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The table shows the relationship between of calories Jacob burns while filler scaring and the number of minutes he roller skates
goldenfox [79]

Answer:

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3 years ago
1. State the problem that Jason has posed in this comic strip?
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3 years ago
convert reapeating decimal where all numbers do not repeat(expert) explain! .13 (3 has a line above it)
aleksley [76]

Answer:

see explanation

Step-by-step explanation:

The bar above the 3 indicates the 3 is being repeated, that is

0.13333....

We require to make 2 equations with the repeating 3 after the decimal point.

let x = 0.13333... , then multiply both sides by 10 then 100

10x = 1.3333 ← equation with repeating 3 after the decimal point

100x = 13.3333 ← second equation with repeated 3 after the decimal point

Subtracting the equations eliminates the repeated 3, that is

100x - 10x = 13.333 - 1.333

90x = 12 ( divide both sides by 90 )

x = \frac{12}{90} ← divide numerator/denominator by 6, hence

0.1333... = \frac{2}{15}

5 0
4 years ago
Read 2 more answers
Calculate y as a function of x when dy/dx = 4x3 + 3x2 - 6x + 5
PtichkaEL [24]
Answer:
y = x⁴ + x³ - 3x² + 5x + C

======

Separable differential equations such as these ones can be solved by treating dy/dx as a ratio of differentials. Then move the dx with all the x terms and move the dy with all the y terms. After that, integrate both sides of the equation.

   \begin{aligned}
\dfrac{dy}{dx} &= 4x^3 + 3x^2 - 6x + 5 \\
dy &= (4x^3 + 3x^2 - 6x + 5) dx \\
\int dy &= \int (4x^3 + 3x^2 - 6x + 5) dx 
\end{aligned}

In general (understood that +C portions are still there), 

   \int x^{m} = \dfrac{x^{m+1}}{m+1}

Note that ∫dy = y  since it is ∫1·dy = ∫y⁰ dy = y¹/(0+1) = y
For the right-hand side, we use the sum/difference rule for integrals, which says that

   \int \big[f(x) \pm g(x)\big]\, dx = \int f(x)\,dx \pm \int g(x) \, dx

Applying these concepts:

   \begin{aligned} 
 \int dy &= \int (4x^3 + 3x^2 - 6x + 5) \, dx \\
y &= \int 4x^3\,dx + \int 3x^2 \, dx - \int 6x\, dx + \int 5\, dx \\
&= \frac{4x^4}{4} + \frac{3x^3}{3} - \frac{6x^2}{2} + 5x + C \qquad \text{(only one $C$ is needed)} \\
&= x^4 + x^3 - 3x^2 + 5x + C
\end{aligned}

The answer is y = x⁴ + x³ - 3x² + 5x + C
6 0
3 years ago
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