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3 years ago

If AB,BC, and AC are 7 inches, 9 inches, and 10 inches, respectively, and XY is 9 inches, find XZ

Mathematics

1 answer:

Ket [755]3 years ago

5 0

Answer:

d) 12.9 in

Step-by-step explanation:

ΔABC ≅ ΔXYZ

AB/AC = XY/XZ

7/10 = 9/XZ

XZ = 10 *9/7

XZ = 12.9

Answer:

d) 12.9 in

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Answer:

See below.

Step-by-step explanation:

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A cube has a side length of 6 cm. What is the volume of the cube, in cubic centimeters

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Answer:

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Step-by-step explanation:

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3 years ago

3(4x-7)=27<br> What does x =?<br> Please help asap im timed!!!

Scilla [17]

Answer:

x = 4

Step-by-step explanation:

3 x ( 4x -7 ) = 27

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3 years ago

On Mars the acceleration due to gravity is 12 ft/sec^2. (On Earth, gravity is much stronger at 32 ft/sec^2.) In the movie, John

insens350 [35]

Solution :

Given initial velocity, v= 48 ft/s

Acceleration due to gravity, g = $12\ ft/s^2$

a). Therefore the maximum height he can jump on Mars is

$H_{max}=\frac{v^2}{2g}$

$H_{max} = \frac{(48)^2}{2 \times 12}$

= 96 ft

b). Time he can stay in the air before hitting the ground is

$T=\frac{2v}{g}$

$T=\frac{2 \times 48}{12}$

= 8 seconds

c). Considering upward motion as positive direction.

v = u + at

We find the time taken to reach the maximum height by taking v = 0.

v = u + at

0 = 16 + (12) t

$t=\frac{16}{12}$

$=\frac{4}{3} \ s$

We know that, $S=ut + \frac{1}{2}at^2$

Taking t = $=\frac{4}{3} \ s$ , we get

$S=16 \times\frac{4}{3} + \frac{1}{2}\times(-12) \times \left(\frac{4}{3}\right)^2$

$S=\frac{32}{3}$ feet

Thus he can't reach to 100 ft as it is shown in the movie.

d). For any jump whose final landing position will be same of the take off level, the final velocity will be the initial velocity.

Therefore final velocity is = -16 ft/s

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3 years ago