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vagabundo [1.1K]
3 years ago
13

There are 330 walnuts in 6 bags. If each bag has the same number of walnuts, how many walnuts are in 2 bags?

Mathematics
2 answers:
Lerok [7]3 years ago
7 0

Answer:

110 walnuts

Step-by-step explanation:

6 bags -> 330 walnuts

Divide 6:

1 bag -> 330\div 6=55

Multiply 2:

2 bags -> 55\times 2 =110

user100 [1]3 years ago
7 0

Answer:

in six bags there are 330 walnuts

in 1 bag there are 330/6 walnuts

in 2 bags there are 330/6*2 =110 walnuts

Step-by-step explanation:

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Answer:

true

Step-by-step explanation:

just my opinion but for me it's true

7 0
2 years ago
Evaluate f(4)<br> f(x) = 3x + 4
RSB [31]
The answer is definitely 7xf
7 0
2 years ago
Helppppp meeeeeseseeeseeee
Ghella [55]

Step-by-step explanation:

Remember: Coplanar definition: In the same plane.

Here, we can see that points G, N, and M make up the intersection of plane K and plane L, so that means our answers are: G, N, and M because we were looking forth e points that are on planes K and L. The other points are not the answer because they are either on only one of the planes or not on any of them at all.

I hope this helps! :)

6 0
3 years ago
Read 2 more answers
3. Solve the system using elimination (not substitution or matrices). negative 2 x plus y minus 2 z equals negative 8A N D7 x pl
riadik2000 [5.3K]

Elimination Method

\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ 5X+2Y-Z=-9 \end{gathered}

If we multiply the equation 3 by (-1) we obtain this:

\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ -5X-2Y+Z=9 \end{gathered}

If we add them we obtain 0, therefore there are infinite solutions. So, let's write it in terms of Z

1. Using the 3rd equation we can obtain X(Y,Z)

\begin{gathered} 5X=-9-2Y+Z \\ X=\frac{-9-2Y+Z}{5} \\  \end{gathered}

2. We can replace this value of X in the 1st and 2nd equations

\begin{gathered} -2\cdot(\frac{-9-2Y+Z}{5})+Y-2Z=-8 \\ 7\cdot(\frac{-9-2Y+Z}{5})+Y+Z=-1 \end{gathered}

3. If we simplify:

\begin{gathered} \frac{-9Y+12Z-63}{5}=-1 \\ \frac{9Y-12Z+18}{5}=-8 \end{gathered}

4. We can obtain Y from this two equations:

\begin{gathered} Y=-\frac{-12Z+58}{9} \\  \end{gathered}

5. Now, we need to obtain X(Z). We can replace Y in X(Y,Z)

\begin{gathered} X=\frac{-9-2Y+Z}{5} \\ X=\frac{-9-2(-\frac{-12Z+58}{9})+Z}{5} \end{gathered}

6. If we simplify, we obtain:

X=\frac{-3Z+7}{9}

7. In conclusion, we obtain that

(X,Y,Z) =

(\frac{-3Z+7}{9},-\frac{-12Z+58}{9},Z)

8 0
11 months ago
What is the tenth term in the sequence 5,8,11,14...? A. 29 B.32 C. 35 D. 38
Andrej [43]
Cause 5+3+8, 8+3=11 11+3=14, so 14+3=17 17+3=20, 20+3=23 23+3=26 26+3=29 29+3=32
so its 5, 8, 11, 14, 17, 20, 23, 26, 29, 32
so the answer is 32
3 0
3 years ago
Read 2 more answers
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