The monochloroderivatives will be obtained by substituting chemically non equivalent hydrogen with chlorine atom, one by one
So the possible monochloro derivatives of 2,4-dimethylpentane (figure 1) are shown in figure (2)
There are 66 neutrons in a single atom of indium-115. The atomic number of indium-115 is 49, meaning there are 49 protons. Then the atomic mass is 115, so 115-49 = 66.
That will make a gold-202 nucleus.
<h3>Explanation</h3>
Refer to a periodic table. The atomic number of mercury Hg is 80.
Step One: Bombard the
with a neutron
. The neutron will add 1 to the mass number 202 of
. However, the atomic number will stay the same.
- New mass number: 202 + 1 = 203.
- Atomic number is still 80.
.
Double check the equation:
- Sum of mass number on the left-hand side = 202 + 1 = 203 = Sum of mass number on the right-hand side.
- Sum of atomic number on the left-hand side = 80 = Sum of atomic number on the right-hand side.
Step Two: The
nucleus loses a proton
. Both the mass number 203 and the atomic number will decrease by 1.
- New mass number: 203 - 1 = 202.
- New atomic number: 80 - 1 = 79.
Refer to a periodic table. What's the element with atomic number 79? Gold Au.
.
Double check the equation:
- Sum of mass number on the left-hand side = 203 = 202 + 1 = Sum of mass number on the right-hand side.
- Sum of atomic number on the left-hand side = 80 = 79 + 1 = Sum of atomic number on the right-hand side.
A gold-202 nucleus is formed.
95.611 g/mol that's the answers
Answer:
wavelength = 6×10⁻⁷m
f = 0.5 ×10¹⁵ Hz
Explanation:
Given data:
Energy of photon = 3.2×10⁻¹⁹ J
Wavelength of photon = ?
Frequency of photon = ?
Solution:
E = h.f
f = frequency
h = planck's constant
E = energy
f = E/h
f = 3.2×10⁻¹⁹ Kg.m².s⁻²/ 6.63×10⁻³⁴ m².Kg/s
f = 0.5 ×10¹⁵ s⁻¹
s⁻¹ = Hz
f = 0.5 ×10¹⁵ Hz
Wavelength:
speed of light = wavelength × frequency
wavelength = speed of light / frequency
wavelength = 3×10⁸ m.s⁻¹ /0.5 ×10¹⁵s⁻¹
wavelength = 6×10⁻⁷m