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levacccp [35]
3 years ago
15

Every 4 years we have a leap year on our calander to make up the extra.......

Physics
1 answer:
OverLord2011 [107]3 years ago
7 0

The Earth takes very nearly (365 and 1/4) days to go around the sun.

If our calendar always had 365 days, then the year would end and re-start
too soon, and the beginning of Spring (and every other season) would
eventually drift into the months after March.

If our calendar always had 366 days, then the year would end and re-start
too late, and the beginning of Spring (and every other season) would
eventually drift into the months before March.

We can't make calendars with an extra quarter-day in each year.  But we
keep them lined up with the real year by saving up the quarters, and adding
one full day to the calendar every 4 years.

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juin [17]

The frequency of light wave is 0.6*10^15 Hz.

The relation between the speed of light, frequency, and wavelength is given as

c=λν

Plugging the values in the above equation

3*10^8=5*10^(-7)*ν

ν=0.6*10^15 Hz.

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6 0
4 years ago
A car accelerates from rest at a constant rate of 3.5m/s^2. What is the velocity of the car 12s later?
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I think 42… sorry if its wrong :( hope it helps..
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3 years ago
Calculate the mass of 1.35 moles of sodium chloride (NaCl).
Harlamova29_29 [7]

Answer:d

Explanation:

4 0
3 years ago
What is the force of gravitational attraction between an object with a mass of 100 kg and another object that has a mass of 300
Leokris [45]

Answer:

5 x 10⁻⁷N

Explanation:

Given parameters:

Mass of object 1  = 100kg

Mass of object 2 = 300kg

Distance  = 2m

Unknown:

Force of gravitational attraction between the objects  = ?

Solution:

Newton's law of universal gravitation states that the gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

From Newton's law of universal gravitation we derive an expression:

       Fg  =  \frac{Gm_{1} m_{2}  }{r^{2} }

G is the universal gravitation constant = 6.67 x 10⁻¹¹

m is the mass

r is the distance between the bodies

Now insert the parameters and solve;

    Fg  = 6.67 x 10⁻¹¹ x \frac{100 x 300}{2^{2} }    = 5 x 10⁻⁷N

7 0
3 years ago
Potential difference is measured in units called
Masja [62]

Answer: Volt

Explanation:

5 0
3 years ago
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