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podryga [215]
4 years ago
12

A baby crawls from x=1.0m to x=4.25m at an average velocity of 0.226 m/s. How much time did it take? (Unit=s)

Physics
1 answer:
postnew [5]4 years ago
3 0

From x = 1.0 m to x = 4.25 m, displacement = 3.25 m

Average velocity of crawling of baby =  0.226 m/s

We know that time taken = Displacement/Time

                                          = \frac{3.25}{0.226}

                                           = 14.38 seconds

So, the baby will take a time of 14.38 seconds from x=1.0m to x=4.25m at an average velocity of 0.226 m/s.

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Mechanics: design a decision tree to determine if an object is experiencing an unbalanced force, and using newton's laws of moti
masya89 [10]

Answer:

The decision designer is a step-wise process

Explanation:

A typical decision tree will be like this:

Are there any forces?

YES - then calculate the resultant forces              NO - Then no calculations are needed

IF YES - Are the forces balanced?                         NO - Then no calculations

IF YES - Then calculations can be done.

Resolve the forces to find the resultant of the forces in the question.

3 0
4 years ago
Which meteorites are the most useful for defining the age of the solar system? Why?
scoundrel [369]

Answer:

meteorite is a piece of interplanetary debris that lives its fiery drops during a through the earth's atmosphere and strikes the surface of the earth.

Explanation:

the meteorites which are most useful for the determination of the age of the solar system are the primitive meteorites. they consist light of colored or grey silicates mixed with metallic grains. the parent bodies of these meteorites are also mostly believed to be pieces asteriods left after they formed in the solar system.

3 0
3 years ago
A book is resting on the table. Forces are exerted _____.
scoray [572]
Forces are exerted I believe : all of the above
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3 0
3 years ago
Read 2 more answers
A point charge q1 = 1.0 µC is at the origin and a point charge q2 = 6.0 µC is on the x axis at x = 1 m.
iris [78.8K]

To solve this problem we will apply the concepts related to the Electrostatic Force given by Coulomb's law. This force can be mathematically described as

F = \frac{kq_1q_2}{d^2}

Here

k = Coulomb's Constant

q_{1,2} = Charge of each object

d = Distance

Our values are given as,

q_1 = 1 \mu C

q_2 = 6 \mu C

d = 1 m

k =  9*10^9 Nm^2/C^2

a) The electric force on charge q_2 is

F_{12} = \frac{ (9*10^9 Nm^2/C^2)(1*10^{-6} C)(6*10^{-6} C)}{(1 m)^2}

F_{12} = 54 mN

Force is positive i.e. repulsive

b) As the force exerted on q_2 will be equal to that act on q_1,

F_{21} = F_{12}

F_{21} = 54 mN

Force is positive i.e. repulsive

c) If q_2 = -6 \mu C, a negative sign will be introduced into the expression above i.e.

F_{12} = \frac{(9*10^9 Nm^2/C^2)(1*10^{-6} C)(-6*10^{-6} C)}{(1 m)^{2}}

F_{12} = F_{21} = -54 mN

Force is negative i.e. attractive

6 0
3 years ago
A 47-kg packing crate is pulled with constant speed across a rough floor with a rope that is at an angle of 37 degrees above the
levacccp [35]

Tension in the rope due to applied force will be given as

F = 142 N

angle of applied force with horizontal is 37 degree

displacement along the floor = 6.1 m

so here we can use the formula of work done

W = F d cos\theta

now we can plug in all values above

W = 142 * 6.1 * cos37

W = 691.8 J

So here work done to pull is given by 691.8 J


8 0
3 years ago
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