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podryga [215]
4 years ago
12

A baby crawls from x=1.0m to x=4.25m at an average velocity of 0.226 m/s. How much time did it take? (Unit=s)

Physics
1 answer:
postnew [5]4 years ago
3 0

From x = 1.0 m to x = 4.25 m, displacement = 3.25 m

Average velocity of crawling of baby =  0.226 m/s

We know that time taken = Displacement/Time

                                          = \frac{3.25}{0.226}

                                           = 14.38 seconds

So, the baby will take a time of 14.38 seconds from x=1.0m to x=4.25m at an average velocity of 0.226 m/s.

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An Olympic diver springs off of a high dive that is 3 m above the surface of the water. When she lands in the water she is trave
klemol [59]

Answer:u=4.51 m/s\ at\ angle\ of\ \theta =59.34^{\circ}

Explanation:

Given

height of building h=3 m

Landing velocity of diver v=8.90 m/s at an angle of 75^{\circ}

Let u be the initial velocity of diver at an angle of \theta with horizontal

Since there is no acceleration in horizontal direction therefore horizontal component of velocity will remain same

u\cos \theta =8.9\cos (75)        ---- -----1

Considering Vertical motion

v^2-u^2=2as

here v=8.9\sin (75)

u=u\sin \theta

s=3 m

a=9.8 m/s^2

(8.9\sin (75))^2-(u\sin \theta )^2=2\times 9.8\times 3

u\sin \theta =\sqrt{(8.9\sin 75)^2-(2\cdot 9.8\cdot 3)}

u\sin \theta =3.886         ----------------2

Divide 2 and 1 we get

\tan \theta =\frac{3.886}{8.9\cos (75)}

\tan \theta =1.687

\theta =59.34^{\circ}

Thus u\cos (59.34)=8.9\cos (75)

u=4.51 m/s

7 0
3 years ago
A car is rounding a 100-m-radius curve at 25 m/s.What is the minimum possible coefficient of static friction between the tires a
Crazy boy [7]

Answer:

The minimum possible coefficient of static friction between the tires and the ground is 0.64.

Explanation:

if the μ is the coefficient of static friction and R is radius of the curve and v is the speed of the car then, one thing we know is that along the curve, the frictional force, f will be equal to the centripedal force, Fc and this relation is :

Fc = f

m×(v^2)/(R) = μ×m×g

    (v^2)/(R) = g×μ

               μ = (v^2)/(R×g)

                  =  ((25)^2)/((100)×(9.8))

                  = 0.64

Therefore, the minimum possible coefficient of static friction between the tires and the ground is 0.64.

4 0
3 years ago
Newtons first law stateS that object will move With a constant velocity if nothing acts on it. Does our every day experience con
bazaltina [42]

Answer:

hi

Explanation:

hi

4 0
3 years ago
Tâm ống dẫn đặt dưới đường phân giới giữa nước và thuỷ ngân h1 = 820mm, chênh lệch chiều cao cột thuỷ ngân h2 = 880mm (Hg = 13,
gayaneshka [121]

Answer:

P = 79993.43245

Explanation:

Được -

Vị trí tâm ống dẫn dưới đường thuỷ ngân h1 = 820 mm

Chênh lệch chiều cao của cột thủy ngân h2 = 880mm

Tỷ trọng của thủy ngân = 13,5951 g / cm3

P = mật độ * gia tốc do trọng lực a * h

Thay thế các giá trị đã cho, chúng ta nhận được -

P = 13,5951 g / cm3 * 980,665 cm / s2 * (88-82) cm

P = 79993.43245

8 0
3 years ago
A wave is produced in a Slinky as shown
ruslelena [56]

Answer:

At point P the direction is left to right Horizontal

5 0
4 years ago
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