The sign associated with the average velocity of the object is negative.
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Average velocity of the object</h3>
The average velocity of the object is calculated as follows;
Average velocity = (v1 + v2)/2
v1 = -20/30 = -0.667 m/s
v2 = 20/50 = 0.4 m/s
Average velocity = (-0.667 + 0.4)/2
Average velocity = -0.134 m/s
Thus, the sign associated with the average velocity of the object is negative.
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Answer:
Both technician are correct.
Explanation:
Remember that Ohm's Law its a relationship between Voltage (E), Current (I) and Resistance (R) in an electrical circuit. This relationship is defined by the following equation:
V=IR
In Ohm's Law you have 3 variables (V,I,R) and 1 equation. It means that you need to know 2 variables (Whatever 2 variables) to know the third.
Technician A says, in other words, that could calculate the Circuit current flow (I) knowing total circuit resistance (R) and total voltage (E). Note that Technician A knows 2 to 3 variables, then it's possible to use Ohm's Law with the following equation:
Technician B says, in other words, that could determine the unknown resistance (R) knowing total current (I) and source voltage (E). Once again, note that Technician B knows 2 to 3 variables, then it's possible to use Ohm's Law with the following equation:
Answer:
Mechanical would have been conserved if only the force of gravity (the weight of the object does work on the system). The tension force does work also on the system but negative work instead. The net force acting of the system is zero since the upward tension in the string suspending the object is equal to the weight of the object but acting in the opposite direction. As a result they cancel out. In the equation above the effect of the tension force on the object has been neglected or not taken into consideration. For the mechanical energy E to be conserved, the work done by this tension force must be included into the equation. Otherwise it would seem as though energy has been generated in some manner that is equal in magnitude to the work done by the tension force.
The conserved form of the equation is given by
E = K + Ug + Wother.
In this case Wother = work done by the tension force.
In that form the total mechanical energy is conserved.
Answer:
18 m
1.1 s
Explanation:
Given:
v₀ = 22 m/s
v = 11 m/s
a = -10 m/s²
Find: Δy
v² = v₀² + 2aΔy
(11 m/s)² = (22 m/s)² + 2 (-10 m/s²) Δy
Δy ≈ 18 m
Find: t
v = at + v₀
11 m/s = (-10 m/s²) t + 22 m/s
t = 1.1 s
Answer : The average speed of cyclist B is 25.714 km/hr
Explanation :
First we have to convert average speed from km/hr to m/s.
Conversion used :
As we are given the average speed of cyclist A 20 km/hr. The average speed in m/s is:
As,
So,
Now we have to calculate the time taken by cyclist A to travel the distance.
conversion used : (1 min = 60 sec)
As per question, cyclist B travels same distance in same time but he took rest for 20 min. That means,
Time taken by cyclist B = 90 min - 20 min = 70 min
Now we have to calculate the average speed of cyclist B.
conversion used : (1 hr = 60 min)
Therefore, the average speed of cyclist B is 25.714 km/hr