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goblinko [34]
3 years ago
7

In a thought experiment, a scientist devised a system in which an object fell from a higher point to a lower point above the gro

und with no friction. Which statement about this system is correct?
The mechanical energy of the system at the beginning of the experiment is less than the mechanical energy of the system at the end of the experiment.

The mechanical energy of the system at the beginning of the experiment is equal to the mechanical energy of the system at the end of the experiment.

The total energy of the system was zero because there was no friction.

The mechanical energy of the system at the beginning of the experiment is greater than the mechanical energy of the system at the end of the experiment.
Physics
1 answer:
timofeeve [1]3 years ago
6 0

Answer:

A. The mechanical energy of the system at the beginning of the experiment is equal to the mechanical energy of the system at the end of the experiment.

Explanation:

I took the quiz and I put this answer and I got a 100%.

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A moon orbits a planet every 42 hours with a mean orbital radius of .002819 AU. The mass of the moon is 8.932 x 1022 kg. Using N
Pepsi [2]

Answer:

The mass of the planet  is 1.9407\times10^{27}\ kg

Explanation:

Given that,

Time period = 42 hours = 151200 sec

Orbital radius = 0.002819 AU = 421716397.5 m

Mass of moon m=8.932\times10^{22}\ kg

We need to calculate the mass of the planet

Using Kepler’s third law

T^2\propto a^3

T^2=\dfrac{4\pi^2}{G(M+m)}\times a^3

Where, a = orbital radius

T = time period

G = gravitational constant

M = mass of moon

m = mass of planet

Put the value into the formula

(151200)^2=\dfrac{4\pi^2}{6.673\times10^{-11}(8.932\times10^{22}+m)}\times(421716397.5)^3

(8.932\times10^{22}+m)=\dfrac{4\pi^2}{6.673\times10^{-11}}\times\dfrac{(421716397.5)^3}{(151200)^2}

(8.932\times10^{22}+m)=1.94087\times10^{27}

m=1.94087\times10^{27}-8.932\times10^{22}

m=1.9407\times10^{27}\ kg

Hence, The mass of the planet  is 1.9407\times10^{27}\ kg

8 0
4 years ago
Calculate the wavelength associated with electrons moving with p.d of 1500v
Artist 52 [7]

Answer:

3.16X10∧-11 m

Explanation:

1/2 mv2 = qV (KE = Electric potential energy)

velocity = √2qV/m = √( 2X 1.6X10∧-19 X 1500/9.11X10∧-31)

2.3X10∧7m/s

now use De Broglie equation

λ = h/mv

= 6.62X10∧-34/( 9.11X10∧-31 X 2.3X10∧7)

3.16 X 10∧-11 m

or

use the above equations and substitute to get the final eqiation

λ = h/√(2mqV) = 3.16X 10∧-11 m

4 0
3 years ago
This is a type of friction experienced within liquids and gases. It depends on:__________.
Aleksandr-060686 [28]

Answer:

(1) how thick the fluid is <u>viscosity</u>

Explanation:

This is a type of friction experienced within liquids and gases. It depends on:__________.

(1) how thick the fluid is_______?

(2) how the shape of the object?

(3) how the speed of the object?

the thickness of a fluid is known as viscosity. the more viscous a fluid is the more frictional force is exerted on an object by the fluid

frictional force is an opposing force that resist the movement of two surfaces in contact, there are to types 0f frictional force

1. static frictional force

2. dynamic frictional force

4 0
3 years ago
d) To calculate air pressure, the volume occupied by air is assumed constant. Why is this incorrect? Explain how the vapor press
Aleks [24]

Answer:

the volume occupied by air is not constant because as we add ethanol in it it will keep decreasing.

vapor pressure calculated and clausius-Claperon plot are affected because volume and vapor pressure are directly proportional.

Explanation:

by charle's law volume and temperature are directly proportional and vapor pressure is directly proportional to temperature thus volume and vapor pressure are also directly proportional by  this relation

3 0
3 years ago
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
masha68 [24]

Answer:

That's hilarious!! :') (Or "That eez 'ilarious!")

Explanation:

Fleur Delacour

7 0
3 years ago
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