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morpeh [17]
3 years ago
14

A patient is placed in an elliptical tank that is 178 centimeters long and 102 centimeters wide to undergo sound wave lithotrips

y treatment for kidney stones. Determine where the sound emitter and the stone should be positioned relative to the center of the tank

Mathematics
1 answer:
DerKrebs [107]3 years ago
5 0

Complete Question

The  diagram for this question is shown on the first uploaded image

Answer:

The position of the emitter is  E =  +  72.9 \  cm\ from\ the\ center

The position of the stone is   S =  - 72.9 \  cm\ from\ the\ center

Step-by-step explanation:

From the question we are told that

   The  length is  l =  178 cm

    The  width is  w  =  102 cm  

Generally the position of the stone along the horizontal axis is mathematically evaluated as

         h  =  \frac{178}{2}

=>      h  = 89 \  cm

Generally the position of the emitter along the vertical axis is mathematically evaluated as

         k =  \frac{102}{2}

=>      k  = 51 \  cm      

Generally the  resultant position of both stone and the emitter is

       R  =  \pm \sqrt{h^ 2  - k^2}

=>     R  = \pm  \sqrt{89^ 2  - 51^2}

=>     R  = \pm 72.9 \  cm

Hence the position of the emitter is  E =  +  72.9 \  cm

            the position of the stone is   S =  - 72.9 \  cm

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