Question

A cat accelerates from rest to 10m/s when it sees a dog. This takes 2 seconds. What was the acceleration of the cat

Answer 1

The formula is a= chance in velocity/time
A=10-0/2
A=10/2
A=5 m/s^2 (meters per second squared)

Answer 2

Answer :

Acceleration of the cat is $a=5\ m/s^2$

Explanation:

It is given that,  

Initial speed of the cat, u =0 (at rest)

Final speed of the cat, v = 10

Time taken, t = 2 s

Let a is the acceleration of the car. We know that the rate of change of velocity of an object is called its acceleration. Mathematically, it is given by :

$a=\dfrac{v-u}{t}$

$a=\dfrac{10-0}{2}$

$a=5\ m/s^2$

So, the acceleration of the cat was $5\ m/s^2$. Hence, this is the required solution.