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Karo-lina-s [1.5K]
3 years ago
13

You have a rectangular Box whose dimensions are 5cm X 4 Cm X 4 Cm that holds 32 jelly beans, and another rectangular Box whose d

imensions are 12cm X 3cm X 3 cm that holds 43 jelly beans. You are pretty sure the Empirical Ratio for Jelly beans in these two boxes is :
A) .04 Jelly beans per cubic centimeter
B) .4 Jelly beans per cubic Centimeter
C) 4 Jelly beans per cubic centimeter
D) 40 Jelly beans per cubic centimeter.
Mathematics
2 answers:
FrozenT [24]3 years ago
7 0
The answer is B hope this helps
Marizza181 [45]3 years ago
3 0

Answer:

.4 Jelly beans per cubic Centimeter

Step-by-step explanation:

Volume = 4*4*5 = 80 cm^3

Ratio = 32beans/80cm^3 = .4beans/cm^3

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(21+21)÷7

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20 points Return to questionItem 4Item 4 20 points Police records in the town of Saratoga show that 13 percent of the drivers st
Sladkaya [172]

Answer:

a) 0.1423

b) 0.2977

c) 0.56

Step-by-step explanation:

For each driver stopped for speeding, there are only two possible outcomes. Either they have invalid licenses, or they do not. The probability of a driver having an invalid license is independent from other drivers. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

13 percent of the drivers stopped for speeding have invalid licenses.

This means that p = 0.13

14 drivers are stopped

This means that n = 14

(a) None will have an invalid license.

This is P(X = 0)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{14,0}.(0.13)^{0}.(0.87)^{14} = 0.1423

(b) Exactly one will have an invalid license.

This is P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{14,1}.(0.13)^{1}.(0.87)^{13} = 0.2977

(c) At least 2 will have invalid licenses.

Either less than 2 have invalid licenses, or at least 2 does. The sum of the probabilities of these events is decimal 1. Mathematically, this is

P(X < 2) + P(X \geq 2) = 1

We want P(X \geq 2)

So

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1) = 0.1423 + 0.2977 = 0.44

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.44 = 0.56

8 0
3 years ago
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