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Pepsi [2]
3 years ago
12

4(x+1)-ax=x+5 solve for x

Mathematics
2 answers:
Kay [80]3 years ago
7 0
    4(x + 1) - ax = x + 5
4(x) + 4(1) - ax = x + 5
     4x + 4 - ax = x + 5
     - x              - x
     3x + 4 - ax = 5
           - 4         - 4
            3x - ax = 1
        x(3) - x(a) = 1
            x(3 - a) = 1
              3 - a   3 - a
                      x = 1/(3 - a)
NemiM [27]3 years ago
6 0
4(x+1)-ax=x+5 

4x+4-ax=x+5

 
    Expand 

4x-ax=x+5-4

 
     Subtract \ 4 \ from \ both \ sides 

4x-ax=x+1 

4x=x+1+ax         Add \ ax \ to \ both \ sides 

4x-x=1+ax

 
         Subtract \ x \ from \ both \ sides 

3x=1+ax

 
 

3x-ax=1&#10;&#10; &#10;            <span>Subtract \ ax \ from \ both \ sides  
</span>
x(3-a)=1&#10;&#10; &#10;    

x= \dfrac{1}{3-a}
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Step-by-step explanation:

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<em>Comment on problem 24</em>

Sometimes it is easier to work parts of a problem out of sequence. Here, finding DS first makes finding x easier.

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