Question

4(x+1)-ax=x+5 solve for x

Answer 1

    4(x + 1) - ax = x + 5
4(x) + 4(1) - ax = x + 5
     4x + 4 - ax = x + 5
     - x              - x
     3x + 4 - ax = 5
           - 4         - 4
            3x - ax = 1
        x(3) - x(a) = 1
            x(3 - a) = 1
              3 - a   3 - a
                      x = 1/(3 - a)

Answer 2

$4(x+1)-ax=x+5$ 

$4x+4-ax=x+5$    $Expand$ 

$4x-ax=x+5-4$     $Subtract \ 4 \ from \ both \ sides$ 

$4x-ax=x+1$ 

$4x=x+1+ax$         $Add \ ax \ to \ both \ sides$ 

$4x-x=1+ax$         $Subtract \ x \ from \ both \ sides$ 

$3x=1+ax$ 

$3x-ax=1$            $Subtract \ ax \ from \ both \ sides$  

$x(3-a)=1$    

$x= \dfrac{1}{3-a}$