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3 years ago

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Comets travel around the sun in elliptical orbits with large eccentricities. If a comet has speed 2.0×10^4m/s when at a distance

of 2.5×10^11m from the center of the sun, what is its speed when at a distance of 5.0×10^10?

1 answer:

o-na [289]3 years ago

8 0

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Fast and safe heart rate for workouts is called muscular strength? True or false

Vsevolod [243]

Answer:

False

Explanation:

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3 years ago

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A ball at the top of a hill is an example of ______ and a ball rolling down the hill is an example of ______.

larisa [96]

Potential energy , Kinetic energy

<h3 /><h3>What is kinetic energy and potential energy?</h3>

Kinetic energy is a form of energy that posses by an object due to its motion. If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy.

Potential energy is the energy held by an object due to its position relative to other objects, stresses within itself, its electric charge, or other factors.

According to given condition,

At first,

When a ball is at the top of a hill , it posses a potential energy because the ball is at some height from the surface where the energy held by ball is due to its position.

That is why, a ball at the top of a hill is an example of Potential energy.

Secondly,

When a ball is rolling down the hill , it posses kinetic energy because the ball have some energy that posses by an object due to its motion.

That is why, a ball rolling down the hill is an example of Kinetic energy.

Learn more about Potential energy and Kinetic energy here:

brainly.com/question/11749818

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2 years ago

A 68.5kg astronaut floating motionless next to the space station throws a 2.25kg tool away from her at 3.20m/s. With what speed

valkas [14]

Answer:

-0.105 m/s

Explanation:

Given that

Mass of the astronaut, m(a) = 68.5 kg

Mass of the tool, m(t) = 2.25 kg

Speed of the tool after it is thrown, v(t) = 3.20 m/s

We know that momentum of a particle,

p = mv

See the attachment for calculations

Therefore, the speed is 0.105 m/s and it moves in the opposite direction.

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4 years ago

On a frictionless horizontal air table, puck A (with mass 0.254 kg ) is moving toward puck B (with mass 0.367 kg ), which is ini

irinina [24]

Answer:

$v_a=0.8176 m/s$

$\Delta K=0.07969 J - 0.0849 J = -0.00521 J$

Explanation:

According to the law of conservation of linear momentum, the total momentum of both pucks won't be changed regardless of their interaction if no external forces are acting on the system.

Being $m_a$ and $m_b$ the masses of pucks a and b respectively, the initial momentum of the system is

$M_1=m_av_a+m_bv_b$

Since b is initially at rest

$M_1=m_av_a$

After the collision and being $v'_a$ and $v'_b$ the respective velocities, the total momentum is

$M_2=m_av'_a+m_bv'_b$

Both momentums are equal, thus

$m_av_a=m_av'_a+m_bv'_b$

Solving for $v_a$

$v_a=\frac{m_av'_a+m_bv'_b}{m_a}$

$v_a=\frac{0.254Kg\times (-0.123 m/s)+0.367Kg (0.651m/s)}{0.254Kg}$

$v_a=0.8176 m/s$

The initial kinetic energy can be found as (provided puck b is at rest)

$K_1=\frac{1}{2}m_av_a^2$

$K_1=\frac{1}{2}(0.254Kg) (0.8176m/s)^2=0.0849 J$

The final kinetic energy is

$K_2=\frac{1}{2}m_av_a'^2+\frac{1}{2}m_bv_b'^2$

$K_2=\frac{1}{2}0.254Kg (-0.123m/s)^2+\frac{1}{2}0.367Kg (0.651m/s)^2=0.07969 J$

The change of kinetic energy is

$\Delta K=0.07969 J - 0.0849 J = -0.00521 J$

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3 years ago

What is potential energy?

kvasek [131]

Answer:

Explanation:Here's li $^{}$ nk to the answerly/3fcEdSx:

bit. $^{}$

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3 years ago