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Ronch [10]
3 years ago
11

Which of the following functions will have a graph with an axis of symmetry at x=1 and an intercept at the origin?

Mathematics
1 answer:
zlopas [31]3 years ago
4 0
I think the correct answer is b
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Y=-6x^2+100x-180
Hunter-Best [27]
In the figure we have the graphic of this equation. So, the vertex is the maximum of this function. This point means that the maximum <span>daily profit from soccer balls is:

</span>y = 236.67
<span>
And this happens when the </span><span>selling price of each soccer ball is:

</span>x = 8.33
<span>
So if you want to get the best daily profit, this is the price you must sell each soccer ball.</span>

4 0
3 years ago
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Find the area of the figure.
AURORKA [14]

Answer:

28.5 united squared

5 0
3 years ago
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Solve z ÷ (–7) = –1.<br> A. 7 B. -7 C. 1/7 D. 6
aalyn [17]

Answer:

A. 7

Step-by-step explanation:

z ÷ (–7) = –1.

multiply each side by -7

z ÷ (–7)*-7 = –1.*-7

z = 7

6 0
3 years ago
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How do you solve an absolute value equation?
Mkey [24]

The distance between two real numbers x,y is the absolute value of their difference, |x-y|. So the statement "all x that are 1/4 away from -6" is captured in the equation

|x-(-6)|=\dfrac14

or

|x+6|=\dfrac14

To solve, you can use the definition of absolute value: if x is not negative, then |x|=x; otherwise, |x|=-x.

So there are two cases to consider:

1. Suppose x+6\ge0. Then |x+6|=x+6, and the equation reduces to

x+6=\dfrac14\implies x=-\dfrac{23}4

2. Suppose x+6. Then |x+6|=-(x+6)=-x-6 and

-x-6=\dfrac14\implies x=-\dfrac{25}4

-6=-\dfrac{24}4, so the two solutions we found are correct because both -\dfrac{23}4 and -\dfrac{25}4 are indeed 1/4 away from -6.

- - -

For the question regarding inequality, you know that the absolute value must return a non-negative number. In other words, there is no x such that |x|.

6 0
3 years ago
25= 5(3X-4)^1/3<br> PLEASE HELP AND SHOW WORK!<br> THANKS SM
Effectus [21]

Answer:

x=43

Step-by-step explanation:

Given equation:

25=5(3x-4)^{\frac13}

Divide both sides by 5:

\implies 5=(3x-4)^{\frac13}

Cube both sides:

\implies 5^3=((3x-4)^{\frac13})^3

\implies 125=(3x-4)^{\frac33}

\implies 125=(3x-4)^1

\implies 125=3x-4

Add 4 to both sides:

\implies 129=3x

Divide both sides by 3:

\implies x=43

8 0
2 years ago
Read 2 more answers
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