a point charge of 5.0 × 10–7 c moves to the right at 2.6 × 105 m/s in a magnetic field that is directed into the screen and has
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Answer:
Explanation:
We are looking for final velocity. Since the ball is thrown horizontally, there is no upwards velocity, so the y dimension here is only useful to us for finding how long the ball was in the air. In the y dimension, here's what we know:
a = -9.8 m/s/s
Δx = -59 m
(again, initial upwards velocity is 0 because the ball was thrown horizontally)
We can put all that together in the equation:
Δx = and filling in:
which simplifies to
and solving for t:
and
t = 3.5 sec
Now we can use that time in the d = rt equation, which is all we need for the horizontal dimension (I'll show you why in just a second). In the horizontal dimension, here's what we know:
a = 0 m/s/s
Δx = 65 m
t = 3.5 sec
Putting that all together in our one-dimensional equation for displacement:
Δx = and acceleration is 0, we can simplify that down to
Δx = which is the exact same thing as d = rt where r is the velocity we are looking for. Filling in:
65 = v(3.5) so
v = 18.6 m/s
That's the velocity with which the ball strikes the ground.