Answer:
About 512 g.
Explanation:
We are given a sample of P₂Cl₅ that contains 179 grams of phosphorus, and we want to determine the grams of chlroine that is present.
Thus, we can convert from grams of phosphorus to moles of phosphorus, moles of phosphorus to moles of chlorine, and moles of chlorine to grams of chlorine.
From the formula, there are two moles of P for every five moles of Cl. The molecular weights of P and Cl are 30.97 g/mol and 35.45 g/mol, respectively. Hence:

In conclusion, there is about 512 grams of chlorine present in the sample.
Alternatively, we can mass percentages. The mass percent of phosphorus in P₂Cl₅ is:

Because there are 179 grams of phosphorus, the total amount of sample present is:

Therefore, the amount of chlorine present is 691.1 g - 179 g, or about 512 g, in agreement with our above answer.
Answer:
P1V1/T1 = P2V2/T2
Explanation:
- Hope that helped! Let me know if you need further explanation. Sorry I didn't give you exaxt one, it was kinda hard to read, but that is the correct answer I put above.
An atom of carbon has 4 electrons in its outermost shell, which means that
<span>its ionic charge is 4+ or 4-
</span>Si is in same group as carbon so its also 4+ or 4-
Germanium is 4+.
Sn is also 2+ or 4+
Pb is usually +2
N2 + 3H2 produces 2NH3 If that is the correct chemical equation.
Reactants
N = 2
H =6
Products
N =2
H= 6
The answer is just one.